Answer:
Step-by-step explanation:
Given that
Group Group One Group Two
Mean 26.00 23.00
SD 2.00 4.00
SEM 0.40 1.21
N 25 11
where group I represents female servers and group II male servers.
We have to calculate confidence interval for 90% for difference in means
The mean of Group One minus Group Two equals 3.00
df = 34
standard error of difference = 0.993
t critical = 2.034 for 90% df 34
Hence confid. interval at 90%
=Mean diff ±2.034 * std error of diff
= (0.98, 5.02)
Answer:
2, 5, 14, 41, 122
Step-by-step explanation:
Using the recursive rule with a₁ = 2
a₂ = 3a₁ - 1 = 3(2) - 1 = 6 - 1 = 5
a₃ = 3a₂ - 1 = 3(5) - 1 = 15 - 1 = 14
a₄ = 3a₃ - 1 = 3(14) - 1 = 42 - 1 = 41
a₅ = 3a₄ - 1 = 3(41) - 1 = 123 - 1 = 122
The first 5 terms are 2, 5, 14, 41, 122
All three triangles are congruent by SAS
Answer:
See below
Step-by-step explanation:
This is just the same as n≤5, which would look like the attached number line.
Answer:
13, 18, 72
Step-by-step explanation:
let x-5 represent the first number, since the first number is 5 less than the third number. let x represent the third number. let 4x represent the third number, since it's four times greater than the third number.
set up an equation, and make it equal to 103:
x-5+x+4x=103
solve:
6x-5=103
6x=108
x=18
so, the third number is 18.
the first number is equal to x-5, so:
18-5=13
the second number is equal to 4x, so:
4(18)=72
so, the three numbers are 13, 18, and 72.
