Answer:
Step-by-step explanation:
Given that the Acme Company manufactures widgets, which have a mean of 60 ounces and a standard deviation of 7 ounces
We know that 95% of the area lie between -2 and 2 std deviations from the mean.
i.e. Probability for lying in the middle of 95%
Z score 
Between 46 and 74 oz.
b) Between 12 and 57
convert into Z score
P(-6.86<z<-0.43)
=0.5-0.1664=0.3336
c) X<30 gives Z<-4.83
i.e. P(X<30) =0.00
Answer: The range of the tree heights at yard work is greater than the range of the tree heights at the grow station
Step-by-step explanation:
yard works: 7,9,7,12,15
The grow station:9,11,6,12,7
mean of yard works = 7+9+7+12+15/5
=50/5=10
mean of grow station=
9+11+6+12+7 /5
=45/5 =9
The mean of tree heights at yard work is greater than that of grow station.
median(tree at yard work):7,7,9,12,15
median=9
median(tree at grow station)=6,7,9,11,12
median=9
The median of the tree height at yard work is equal to the median of that of tree station.
Range(yard work) = 15 - 7 =8
Range (tree station) =12-6=6
The range of the tree heights at yard work is greater to the tree heights at that of tree station
Being honest, you should searxh number lines to see if that helps first. Hope thid helps! <3
Answer:
x = 47/10
Step-by-step explanation:
Step 1: Write equation
51 - 14x = 4 - 4x
Step 2: Solve for <em>x</em>
- Add 14x to both sides: 51 = 4 + 10x
- Subtract 4 on both sides: 47 = 10x
- Divide both sides by 10: x = 47/10
Solve (x+3) / 3x > 2 . [I guess 3x divides (x+3) and not 3], if so, then
(x+3) > 6x → 3 > 6x-x → OR x < 3/5 OR x<0.6
