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Kruka [31]
3 years ago
10

Sally had 57 apples if she gave 48 to charity how many apples does she have left

Mathematics
1 answer:
marin [14]3 years ago
4 0

Answer:

ig it equals 9- n e ways ye- I rp as killua :3

Step-by-step explanation:

:3

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What is the sum of the roots of the polynomial shown below?<br> f(x) = x^3 + 2x^2 - 11x-12
svp [43]

<u>Answer:  </u>

Sum of the roots of the polynomial x^{3}+2 x^{2}-11 x-12 \text { is }-2

<u>Solution:</u>

The general form of cubic polynomial is a x^{3}+b x^{2}+c x+d=0 ---- (1)

If we have any cubic polynomial a x^{3}+b x^{2}+c x+d=0 having roots \alpha , \beta , \theta

Sum of roots \alpha + \beta + \theta = \frac{-b}{a} ---(2)

From question given that,

x^{3}+2 x^{2}-11 x-12 --- (3)

On comparing equation (1) and (3), we get a = 1, b = 2, c = -11 and d = -12

Hence the sum of roots using eqn 2 is given as,

= \frac{-2}{1}

= -2

Hence the sum of the roots of the polynomial x^{3}+2 x^{2}-11 x-12 \text { is }-2

4 0
2 years ago
Help...............!
Neporo4naja [7]

Answer:

<h3>I had an advise that math antics can help u </h3>

Step-by-step explanation:

<h3>Thank you</h3>
5 0
1 year ago
A bank features a savings account that has an annual percentage rate of 3.5% with interest compounded quarterly. Vanessa deposit
vazorg [7]

Answer:

APY = 0.04 or 4%

Step-by-step explanation:

Given the annual percentage rate of 3.5% that is compounded quarterly, and a principal of $6,500:

We can use the following formula to solve for the annual percentage yield (APY):

APY =  (1 + \frac{r}{n})^n - 1

where <em>r</em> = interest rate = 3.5% or 0.035

<em>           n</em> = number of compounding periods per year = 4

We can plug in the values into the equation:

APY =  (1 + \frac{r}{n})^n - 1

APY =  (1 + \frac{.035}{4})^4 - 1

APY =  (1 + 0.00875)^4 - 1

APY =  (1.00875)^4 - 1

APY = 1.03546 - 1  

APY = 0.04 or 4%        

8 0
2 years ago
What is the simplified form of 2/x^2-x - 1/x?
Pachacha [2.7K]

Answer:  \bold{(C)\ \dfrac{3 - x}{x(x-1)}}

<u>Step-by-step explanation:</u>

   \dfrac{2}{x^2-x}-\dfrac{1}{x}

=\dfrac{2}{x(x-1)}+\dfrac{-1}{x}

=\dfrac{2}{x(x-1)}+\dfrac{-1}{x}\bigg(\dfrac{x-1}{x-1}\bigg)

=\dfrac{2}{x(x-1)}+\dfrac{-x+1}{x(x-1)}

=\dfrac{2-x+1}{x(x-1)}

=\dfrac{3-x}{x(x-1)}

8 0
3 years ago
Mai says that the equation 2x + 2 = x + 1 has no solution because the left-hand side is double the right hand side.
zhannawk [14.2K]

Answer:

h im billy

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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