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Zolol [24]
3 years ago
5

A circle is entered on the point (-1,5) and contains the point (7,11). What is the area of this circle?

Mathematics
1 answer:
bezimeni [28]3 years ago
8 0

The answer is 100.

<u>Step-by-step explanation</u>:

<u>Given</u>:

A circle is centered on the point(-1,5) and contains the point(7,11)

<u>To find</u>:

Area of a circle.

<u>Formula</u>:

(x – a)2 + (y – b)2 = r2

<u>Solution</u>:

D(A,B)=√ (xa − xb)2 + (ya − yb)2

D(A,B)=√ (7 + 1 )2 + (11− 5)2

D(A,B)=√ (8 )2 + (6)2

D(A,B)=√ 100

D(A,B)=10

Substituting in the above equation

(x + 1 )2 + (y – 5)2 = 100

                                                                                     

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titutex=cos\alp,\alp∈[0:;π]

\displaystyle Then\; |x+\sqrt{1-x^2}|=\sqrt{2}(2x^2-1)\Leftright |cos\alp +sin\alp |=\sqrt{2}(2cos^2\alp -1)Then∣x+

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