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Sever21 [200]
3 years ago
6

Please Help! The graph of y=f(x) is shown below. What are all of the real solutions of f(x)=0? (Picture of graph included)

Mathematics
1 answer:
qwelly [4]3 years ago
6 0

Answer:

(7, 0), (-8, 0), (0, 0)

Step-by-step explanation:

y = f(x) = 0

the real solutions are the ones that cross the x-axis because when a point is on the x-axis, its y coordinate will be 0.

=> (7, 0), (-8, 0), (0, 0)

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which of the following best describes 4^2/3? a. sq root of 16, b. cube root of 4, c. sq root of four, d. cube root of 16
son4ous [18]

Answer: D) cube root of 16

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Explanation:

The rule we use is

x^{m/n} = \sqrt[n]{x^m}

In this case, x = 4, m = 2 and n = 3.

So,

x^{m/n} = \sqrt[n]{x^m}\\\\\\4^{2/3} = \sqrt[3]{4^2}\\\\\\4^{2/3} = \sqrt[3]{16}\\\\\\

Showing that the original expression turns into the cube root of 16.

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Step-by-step explanation:

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3 years ago
Which equation is true when r = 7 ?
jeka57 [31]

Answer:

7 = 49 ÷ r

Step-by-step explanation:

To find the equation that is true when r = 7, we need to find a number after the equals sign that is a multiple of 7.

Multiples of 7:  

7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77...

Therefore, the only answer option in which the number after the equals sign is a multiple of 7 is:

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To prove this, input r = 7 into each of the equations:

   6 = 30 ÷ r

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⇒ 7 = 54 ÷ 7

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⇒ 7 = 49 ÷ 7

⇒ 7 = 7 ← correct!

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2 years ago
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