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2 years ago

9

A razor atv initially sold for $18000 and is now on sale for $16500

1 answer:

Sav [38]2 years ago

8 0

I know A is decrease i dont know B

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Describe how to round 3.987 to the nearest tenth.

Inga [223]

Answer:

4

Step-by-step explanation:

You see the hunderth digit has a 8, so you round up. 0.9+0.1=1 so you add 1 to 3, so 3.987 rounded is 4

4 0

2 years ago

Read 2 more answers

On a number line is 2.06 or 2.6 farther to the left

mel-nik [20]

2.06 because the lower the number, the further left it will be on a number line

7 0

2 years ago

Plz answer correctly I don’t wanna fail plz answer!!!!!not much!!!!!!!

Triss [41]

I’m pretty sure yes it is

6 0

2 years ago

Evaluate the function at the indicated values if possible. If an indicated value is not in the domain, say so.

goldfiish [28.3K]

Answer:

f(-7)=0.

f(2)=-9/5.

f(3) doesn't exist because 3 isn't in the domain of the function.

Step-by-step explanation:

$f(x)=\frac{x+7}{x^2-9}$ is the given function.

We are asked to find:

$f(-7)$

$f(2)$

$f(3)$ .

f(-7) means to replace x in the expression called f with -7:

Evaluate $\frac{x+7}{x^2-9}$ at $x=-7$

$\frac{(-7)+7}{(-7)^2-9}$

$\frac{0}{49-9}$

$\frac{0}{40}$

$0$

So f(-7)=0.

f(2) means to replace x in the expression called f with 2:

Evaluate $\frac{x+7}{x^2-9}$ at $x=2$

$\frac{2+7}{2^2-9}$

$\frac{9}{4-9}$

$\frac{9}{-5}$

$\frac{-9}{5}$

So f(2)=-9/5

f(3) means to replace x in the expression called f with 3:

Evaluate $\frac{x+7}{x^2-9}$ at $x=3$

$\frac{3+7}{3^2-9}$

$\frac{10}{9-9}$

$\frac{10}{0}$

Division by 0 is not allowed so 3 is not in the domain of our function.

5 0

3 years ago

Please answer according to the picture.

katen-ka-za [31]

-4 and 2 are the solutions, since that is where they intercept the x axis, and when plugged into the equation, make it true.

6 0

3 years ago