Answer:
x³+3x²+3x+1
Step-by-step explanation:
=(x+1)(x+1)(x+1)
=(x+1)(x²+x+x+1)
=(x+1)(x²+2x+1)
=(x³+2x²+x+x²+2x+1)
=x³+3x²+3x+1
Answer:
x=-8/3
Step-by-step explanation:
group like terms: -3x+-6x=-9x
add 2 to both sides: 2+22=24
divide both sides by -9: -9x/-9=24/-9
x=-8/3
Answer:
Step-by-step explanation:
Given that,
f(3) = 2
f'(3) = 5.
We want to estimate f(2.85)
The linear approximation of "f" at "a" is one way of writing the equation of the tangent line at "a".
At x = a, y = f(a) and the slope of the tangent line is f'(a).
So, in point slope form, the tangent line has equation
y − f(a) = f'(a)(x − a)
The linearization solves for y by adding f(a) to both sides
f(x) = f(a) + f'(a)(x − a).
Given that,
f(3) = 2,
f'(3) = 5
a = 3, we want to find f(2.85)
x = 2.85
Therefore,
f(x) = f(a) + f'(a)(x − a)
f(2.85) = 2 + 5(2.85 - 3)
f(2.85) = 2 + 5×-0.15
f(2.85) = 2 - 0.75
f(2.85) = 1.25
Answer:
Putting the value in x = 2 , y =4 in 2x - 2y we get,
2 × 2 - 4× 2= 4-8 = -4
Putting the value in z = 3 in z - 5 we get,
z - 5 = 3 - 5 = -2
Hopes this helps:
Answer:
12 1/3
