Answer:
x = 13
y = -10
z = -7
Step-by-step explanation:
x+y+z=−4
2x+3y−2z=10
−x+2y−3z=−12
Add the first and the third equations to eliminate x
x+y+z=−4
−x+2y−3z=−12
--------------------
3y -2z = -16 Equation A
Add the second and twice the third equation to eliminate x
2x+3y−2z=10
−2x+4y−6z=−24
----------------------------
7y -8z = -14 Equation B
Take Equation A and multiply by -4
-4*( 3y -2z) = (-16)*-4
-12y + 8z = 64
Add this to Equation B
-12y + 8z = 64
7y -8z = -14
-----------------------
-5y = 50
Divide by -5
-5y/-5 = 50/-5
y = -10
Now using equation A
3y -2z = -16
3*-10 -2z = -16
-30 -2z = -16
Add 30 to each side
-2z = -16+30
-2z = 14
Divide by -2
-2z/-2 = 14/-2
z = -7
Now find x using the first equation
x+y+z = -4
x -7-10 = -4
x -17 = -4
Add 17 to each side
x-17+17 = -4+17
x = 13
Answer: b > 16
Step-by-step explanation:
Because a > -25, b must be at least greater than 16, as if a is -25.1, for example, b must be 16.11.
Answer:
A. sides
Step-by-step explanation:
Hello from MrBillDoesMath!
Answer: 21
Discussion:
g(3) = 3^2 -2 = 9 -2 = 7 =>
f(g(3)) = f (
7) = 2(7) + 7 = 14 + 7 = 21
Thank you,
MrB
Answer:
1/2
Step-by-step explanation:
The interior of the square is the region D = { (x,y) : 0 ≤ x,y ≤1 }. We call L(x,y) = 7y²x, M(x,y) = 8x²y. Since C is positively oriented, Green Theorem states that
Lets calculate the partial derivates of M and L, Mx and Ly. They can be computed by taking the derivate of the respective value, treating the other variable as a constant.
- Mx(x,y) = d/dx 8x²y = 16xy
- Ly(x,y) = d/dy 7y²x = 14xy
Thus, Mx(x,y) - Ly(x,y) = 2xy, and therefore, the line ntegral is equal to the double integral
We can compute the double integral by applying the Barrow's Rule, a primitive of 2xy under the variable x is x²y, thus the double integral can be computed as follows
We conclude that the line integral is 1/2
