All categories

3 years ago

12 friends shared 8 small pizzas equally how much pizza did each person get?

Mathematics

2 answers:

timofeeve [1]3 years ago

6 0

To get the answer you have to do 12 divided by 8
12/8=1.5
So everyone got 1 and 1/2 pizzas per person

natali 33 [55]3 years ago

4 0

12 divided by 8 and you'll get your answer of 1.5 (:

You might be interested in

Starbucks sells their coffee for $3.36 for 24 ounces

Llana [10]

Answer:

Starbucks by 1 cent difference.

Step-by-step explanation:

Divide: 3.36 divided by 24 to find Starbucks. You get 14 cents per ounce

Divide: 2.40 divided by 16 to find Circle K. You get 15 cents per ounce

Compare: Starbucks is cheaper by 1 cent.

8 0

2 years ago

Read 2 more answers

Julli [10]

Answer:

x = 2

Step-by-step explanation:

AB/BC = AD/DE

$\frac{2}{1}$ = $\frac{2+x}{2}$

cross-multiply:

2+x = 4

x = 2

7 0

3 years ago

Determine all prime numbers a, b and c for which the expression a ^ 2 + b ^ 2 + c ^ 2 - 1 is a perfect square .

kogti [31]

Answer:

The family of all prime numbers such that $a^{2} + b^{2} + c^{2} -1$ is a perfect square is represented by the following solution:

$a$ is an arbitrary prime number. (1)

$b = \sqrt{1 + 2\cdot a \cdot c}$ (2)

$c$ is another arbitrary prime number. (3)

Step-by-step explanation:

From Algebra we know that a second order polynomial is a perfect square if and only if $(x+y)^{2} = x^{2} + 2\cdot x\cdot y + y^{2}$ . From statement, we must fulfill the following identity:

$a^{2} + b^{2} + c^{2} - 1 = x^{2} + 2\cdot x\cdot y + y^{2}$

By Associative and Commutative properties, we can reorganize the expression as follows:

$a^{2} + (b^{2}-1) + c^{2} = x^{2} + 2\cdot x \cdot y + y^{2}$ (1)

Then, we have the following system of equations:

$x = a$ (2)

$(b^{2}-1) = 2\cdot x\cdot y$ (3)

$y = c$ (4)

By (2) and (4) in (3), we have the following expression:

$(b^{2} - 1) = 2\cdot a \cdot c$

$b^{2} = 1 + 2\cdot a \cdot c$

$b = \sqrt{1 + 2\cdot a\cdot c}$

From Number Theory, we remember that a number is prime if and only if is divisible both by 1 and by itself. Then, $a, b, c > 1$ . If $a$ , $b$ and $c$ are prime numbers, then $2\cdot a\cdot c$ must be an even composite number, which means that $a$ and $c$ can be either both odd numbers or a even number and a odd number. In the family of prime numbers, the only even number is 2.