Step-by-step explanation:
In the first part, he was travelling with twice the speed, or Vs, for distance
48 - d, for 2 hours.
speed = distance/time
distance = speed * time
First part :
48 - d = 2V * 2
⇒d + 4V = 48
Second part:
d = V * 2
⇒d = 2V
Substitute 2s for d in equation 1.
2s + 4s = 48
6s = 48
s = 8
The speed in the second part is 8 mph.
<u>The speed in the first part is 2s = 2(8) = 16</u>
I hope this helps
Answer:
1/63
Step-by-step explanation:
There are a couple of ways to do this.
<h3>1) </h3>
Look for the GCF of the numerators when a common denominator is used.
GCF(3/7, 4/9) = GCF(27/63, 28/63) = (1/63)·GCF(27, 28)
GCF(3/7, 4/9) = 1/63
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<h3>2) </h3>
Use Euclid's algorithm. If the remainder from division of the larger by the smaller is zero, then the smaller is the GCF; otherwise, the remainder replaces the larger, and the algorithm repeats.
(4/9)/(3/7) = 1 remainder 1/63*
(3/7)/(1/63) = 27 remainder 0
The GCF is 1/63.
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* The quotient is 28/27 = 1 +1/27 = 1 +(1/27)(3/7)/(3/7) = 1 +(1/63)/(3/7) or 1 with a remainder of 1/63.
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<em>Additional comment</em>
3/7 = (1/63) × 27
4/9 = (1/63) × 28
Answer:
b=4
Step-by-step explanation:
P.T.c^2=a^2 +b^2
5^2=3^2 +b^2
25=9+b^2
b^2 =25-9
b^2 =16
b=sqrt(16)
b=4
