Determine 2nd term and rth term of a.p.whose 6 th term is 12 and 8 th term is 22
1 answer:
Answer:
see explanation
Step-by-step explanation:
The n th term of an arithmetic progression is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Given = 12 and
= 22, then
a₁ + 5d = 12 → (1)
a₁ + 7d = 22 → (2)
Subtract (1) from (2) term by term to eliminate a₁
2d = 10 ( divide both sides by 2 )
d = 5
Substitute d = 5 into (1) to find a₁
a₁ + 5(5) = 12
a₁ + 25 = 12 ( subtract 25 from both sides )
a₁ = - 13
Thus
= - 13 + 5 = - 8
= - 13 + 5(n - 1) = - 13 + 5n - 5 = 5n - 18 ← n th term
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By using trigonometric relations, we will see that:
AC = 15.6 in
AB = 8.4 in.
<h3>How to get the measures of the other two sides of the right triangle?</h3>Here we have the right triangle where:
B = 90°
C = 40°
BC = 10 in.
Notice that is the adjacent cathetus to the angle C, then we can use the two relations:
- sin(a) = (adjacent cathetus)/(hypotenuse).
- tan(a) = (opposite cathetus)/(adjacent cathetus).
Where:
- hypotenuse = AC
- opposite cathetus = AB.
Then we will have:
sin(40°) = 10in/AC.
AC = 10in/sin(40°) = 15.6 in
tan(40°) = AB/10in
tan(40°)*10in = AB = 8.4 in.
So we can conclude that for the given right triangle we have:
AC = 15.6 in
AB = 8.4 in.
If you want to learn more about right triangles:
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