Answer:
4. A
5. B
Step-by-step explanation:
4. I'll solve question four first:
The two marked points on the line are (-2, -3)&(2, 5). Using the formula to find slope(y2-y1/x2-x1), substitute in the points.
5--3/2--2 or 8/4;simplified to 2/1 or 2.
Now use point-slope form: y-y1 = m(x-x1)
y--3 = 2(x--2): Substitute in the values of y1, m, and x1.
y+3 = 2x + 4: Distribute.
y = 2x + 1: Subtract three from both sides.
5. Do the same for question 5.
The first point is (-4, 2), the second point is (4, -1).
-1-2/4--4; -3/8.
Now use point-slope form:
y-2 = -3/8x -12/8: Substitute in the values of x1, y1, m, and distribute the slope to the parentheses.
y = -3/8x + 1/2
BD=10 because it is symmetrical to AD.
There'll be 5 parents that'll go to the museum
Let the number of parents that will go to the museum be represented by x.
Based on the information given, the equation to use will be:
15/75 = x/25
Cross multiply
75 × x = 15 × 25
75x = 375
Divide both side by 75
75x/75 = 375/75
x = 5
Therefore, there'll be 5 parents that'll go to the museum.
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Answer:
(x-y) (a+x-y)
Step-by-step explanation:
(y-x)=-(x-y)
-a(y-x) = a(x-y)
(x-y)^2 = (x-y)(x-y)
(x-y)(a + x - y)
Given: KL is a tangent to the circle.
LM is another tangent to the circle.
We can use the tangent meeting at an external point theorem.
<em>Theorem</em>: <em>The tangent segments to a circle from an external point are equal.
</em>
Thus, we can say KL = LM, as they lie on a common circle, and are tangents to such circle.
4x - 2 = 3x + 3
4x - 3x = 3 + 2
x = 5
Since LM is 3x + 3, we can substitute the value of x to LM to render:
3(5) + 3 = 18
Thus, LM = KL = 18 units.
