X=6
First subtract 11 from both sides and you'll get 5x^2=180 then divide 180 by 5 which equals 36 you get x^2=36 find square root of 36 is 6
It is in form (x,y) (ususally)
7.5 and 12
there is something called a coordinate system where a line called the y axis runs vertically for infinity and a line perpendicular to it, crosses it. the other line is called the x axis which also extends for infinity
the point where they cross is point (0,0) or the origin
basically the numbers tell you how far you are from the axises
on the y axis, + numbers are up and - numbers are down
on the x axis, + numbers are to the right and - numbers are to the left
7.5=x and 12=y
+7.5 is positive
7.5 means that the point is 7.5 units to the right of the origin in relation to the x axis
12 is positive
12 means that the point is 12 units up from the origin in relation to the y axis
hope this helped. feel free to ask if its too confusing
<span> 2(lh + lw + wh) = 96
lh + lw + wh = 48
l(h + w) + wh = 48
3(3 + 4) + 12
Length = 3
Width = 3
Height = 4
</span>
Answer/Step-by-step explanation:
1. Side CD and side DG meet at endpoint D to form <4. Therefore, the sides of <4 are:
Side CD and side DG.
2. Vertex of <2 is the endpoint at which two sides meet to form <2.
Vertex of <2 is D.
3. Another name for <3 is <EDG
4. <5 is less than 90°. Therefore, <5 can be classified as an acute angle.
5. <CDE is less than 180° but greater than 90°. Therefore, <CDE is classified as an obtuse angle.
6. m<5 = 42°
m<1 = 117°
m<CDF = ?
m<5 + m<1 = m<CDF (angle addition postulate)
42° + 117° = m<CDF (Substitution)
159° = m<CDF
m<CDF = 159°
7. m<3 = 73°
m<FDE = ?
m<FDG = right angle = 90°
m<3 + m<FDE = m<FDG (Angle addition postulate)
73° + m<FDE = 90° (Substitution)
73° + m<FDE - 73° = 90° - 73°
m<FDE = 17°
Answer:
(a) 
(b) Domain: 
<em>(See attachment for graph)</em>
(c) 
Step-by-step explanation:
Given
Solving (a): A function; l in terms of w
All we need to do is make l the subject in
Divide through by 2
Subtract w from both sides
Reorder
Solving (b): The graph
In (a), we have:
Since l and w are the dimensions of the fence, they can't be less than 1
So, the domain of the function can be
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To check this
When 
When 
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<em>See attachment for graph</em>
<em></em>
Solving (c): Write l as a function 
In (a), we have:
Writing l as a function, we have:
Substitute for l in
becomes
