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EastWind [94]
3 years ago
6

Avery wants to make a triangular garden but needs to fence it in to keep rabbits out.How can she figure out how much fencing to

buy
Mathematics
1 answer:
nexus9112 [7]3 years ago
3 0
Find the perimeter of the garden find out what kind of triangle the garden is for example if it is a right triangle it has to equal up to 90.

To find the area remember that A=b•h2 as a=area
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I NEED Help Please!!
Dmitry [639]

Answer:

27

Step-by-step explanation:

You add. hope it helps ;)

8 0
3 years ago
De acuerdo con la tercera ley de movimiento planetario de Kepler, la masa de un planeta es directamente proporcional al cubo de
Sunny_sXe [5.5K]

Answer:

La masa del Sol es 2.509\times 10^{31} kilogramos.

Step-by-step explanation:

Tras una lectura cuidadosa al enunciado, tenemos que la Tercera Ley de Kepler queda descrita por la siguiente relación:

M \propto \frac{r^{3}}{T^{2}}

M = k\cdot \frac{r^{3}}{T^{2}} (Eq. 1)

Donde:

r - Distancia entre los centros del planeta y el satélite, medido en kilómetros.

T - Período oribital del satélite, medido en días.

k - Constante de proporcionalidad, medida en kilogramo-días cuadrados por kilómetro cúbico.

M - Masa del planeta, medida en kilogramos.

Podemos obtener la masa del Sol mediante la siguiente relación:

\frac{M_{S}}{M_{E}} = \frac{\frac{r_{E}^{3}}{T_{E}^{2}} }{\frac{r_{M}^{3}}{T_{M}^{2}} }

\frac{M_{S}}{M_{E}} = \left(\frac{T_{M}}{T_{E}} \right)^{2}\cdot \left(\frac{r_{E}}{r_{M}} \right)^{3} (Eq. 2)

Donde:

T_{M}, T_{E} - Períodos orbitales de la Luna y la Tierra, medidos en días.

r_{E}, r_{M} - Distancias entre la Tierra y el Sol, así como entre la Luna y la Tierra, medidas en kilómetros.

M_{S}, M_{E} - Masas del Sol y la Tierra, medidos en kilogramos.

Si M_{E} = 75.97\times 10^{24}\,kg, T_{E} = 365.3\,d, T_{M} = 27.3\,d, r_{M} = 3.84\times 10^{5}\,km y r_{E} = 1.496\times 10^{8}\,km, entonces tenemos que la masa del Sol es:

M_{S} = \left(\frac{T_{M}}{T_{E}} \right)^{2}\cdot \left(\frac{r_{E}}{r_{M}} \right)^{3}\cdot M_{E}

M_{S} = \left(\frac{27.3\,d}{365.3\,d} \right)^{2}\cdot \left(\frac{1.496\times 10^{8}\,km}{3.84\times 10^{5}\,km} \right)^{3}\cdot (75.97\times 10^{24}\,kg)

M_{S} = 2.509\times 10^{31}\,kg

La masa del Sol es 2.509\times 10^{31} kilogramos.

7 0
3 years ago
What expression is equivalent to 3(x-2)+2x
WINSTONCH [101]

Answer:5x - 6

Step-by-step explanation:

4 0
3 years ago
I need some help so if someone could help with shown work
murzikaleks [220]

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8 0
3 years ago
What x-value makes the set of ratios equivalent? Tiles 2 : 3 = 6 : x ,4 : 7 = x : 42 , 2x : 48 = 3 : 12, 12 : 15 = x : 20
Naya [18.7K]

Step-by-step explanation:

2 : 3 = 6 : x ,

Ratio can be written as

\frac{2}{3} = \frac{6}{x}

2*3 = 6, we multiply top  and bottom of fraction by 3

\frac{2*3}{3*3} = \frac{6}{9}

So value of x=9

4 : 7 = x : 42 ,

\frac{4}{7} = \frac{x}{42}

7*6 = 42, we multiply top  and bottom of fraction by 6

\frac{4*6}{7*6} = \frac{24}{42}

So value of x=24

2x : 48 = 3 : 12,

\frac{2x}{48} = \frac{3}{12}

\frac{3}{12}[/tex] = \frac{2x}{48}12*4 = 48, we multiply top  and bottom of fraction by 4[tex]\frac{3*4}{12*4} = \frac{12}{48}

2x= 12, so x= 6

12 : 15 = x : 20

\frac{12}{15} = \frac{x}{20}

15 * \frac{4}{3} = 20,

we multiply top  and bottom   by 4/3

 12 * \frac{4}{3} = 16

So value of x=16

4 0
3 years ago
Read 2 more answers
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