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bogdanovich [222]
3 years ago
9

PLEASE HELP ME!!!! WILL MARK BRAINLIEST

Mathematics
2 answers:
FromTheMoon [43]3 years ago
8 0

Answer:

5

Step-by-step explanation:

Pythagoras's theorem dictates that  a squared + b squared  = c squared when talking about sides on right angled triangles with a and b being flat sides and c being the hypotenuse which gives us the forumula below

3 squared + 4 squared = 25 route 25 = 5

son4ous [18]3 years ago
8 0

Answer:

Step-by-step explanation:

Distance=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}\\\\d_{3}=\sqrt{(2-[-1])^{2}+(0-4)^{2}}\\\\ =\sqrt{(2+1)^{2}+(-4)^{2}}\\\\ =\sqrt{(3)^{2}+(-4)^{2}}\\\\=\sqrt{9+16}\\\\ =\sqrt{25}\\\\ =5

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we conclude that at 5:00 p.m. there are 8 more inches of snow than at 8:00 a.m.

<h3>How many more inches of snow were on the ground at 5:00 p.m. than at 8:00 a.m.?</h3>

We know that at 8:00 a.m. there were t inches of snow in the ground.

At 5:00 p.m. there were 3t inches of snow in the ground.

Then the difference between the heights of the snow is:

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And we know that at 5:00 p.m. there were 12 inches of snow then we can solve the linear equation for t:

3t = 12in

t = (12in)/3 = 4 in

Replacing that in the difference of heights:

2t = 2*4in = 8in

From this, we conclude that at 5:00 p.m. there are 8 more inches of snow than at 8:00 a.m.

If you want to learn more about linear equations:

brainly.com/question/1884491

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2 years ago
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