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Leto [7]
3 years ago
5

A spinner with six sections labeled A through F is spun. The probability of spinning a consonant (B, C, D, or F) is 23 . What is

the probability of not spinning a consonant? Enter your answer as a fraction, in simplest form, in the box.
Mathematics
2 answers:
Illusion [34]3 years ago
7 0
1-\dfrac{2}{3}=\dfrac{1}{3}

It's 1/3.
svetoff [14.1K]3 years ago
4 0

Answer: \frac{1}{3}

Step-by-step explanation:

Given: A spinner with six sections labeled A through F is spun.

The probability of spinning a consonant (B, C, D, or F) =\frac{2}{3}

Then, the probability of not spinning a consonant

= 1 - probability of spinning a consonant

Thus, the probability of not spinning a consonant =1-\frac{2}{3}

Hence, the probability of not spinning a consonant =\frac{1}{3}

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