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liberstina [14]
4 years ago
10

Square root of 1269 pl pl answer

Mathematics
2 answers:
Fiesta28 [93]4 years ago
7 0
Square root of 1269 = 35.62
Allisa [31]4 years ago
5 0
Your answer will be 3<span>√</span>141 or 35.62302626
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Is x(4x^2+8x+12) completely factored? If not how else can it be factored ?
NikAS [45]
B......……...................
7 0
3 years ago
The length of the base of a triangle is twice its height. if the area of the triangle is 121 square​ kilometers, find the height
mariarad [96]
B = 2h

Area = 121
1/2 × b × h = 121
1/2 × 2h × h = 121
h × h = 121
h^2 = 121
h = square root of 121
h = 11

The height is 11 kilometers
3 0
3 years ago
A county is considering rasing the speed limit on a road because they claim that the mean speed of vehicles is greater than 30 m
DochEvi [55]

Answer:

No, at alpha equals 0.10​, we do not have enough evidence to support the​ county's claim.

Step-by-step explanation:

We are given that a county is considering raising the speed limit on a road because they claim that the mean speed of vehicles is greater than 30 miles per hour.

A random sample of 15 vehicles has a mean speed of 31 miles per hour and a standard deviation of 4.7 miles per hour.

<em><u>Let </u></em>\mu<em><u> = true mean speed of the vehicles.</u></em>

SO, <u>Null Hypothesis</u>, H_0 : \mu \leq  30 miles per hour   {means that the mean speed of vehicles is lesser than or equal to 30 miles per hour}

<u>Alternate Hypothesis,</u> H_A : \mu > 30 miles per hour   {means that the mean speed of vehicles is greater than 30 miles per hour}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                        T.S.  = \frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean speed of 15 vehicles = 31 mph

             s = sample standard deviation = 4.7 mph

             n = sample of vehicles = 15

So, <em><u>test statistics</u></em>  =   \frac{31-30}{\frac{4.7}{\sqrt{15} } }  ~ t_1_4

                               =  0.824

<u><em>Hence, the value of test statistics is 0.824.</em></u>

<em />

<em>Now at 0.10 significance level, the t table gives critical value of 1.345 at 14 degree of freedom for right-tailed test. Since our test statistics is less than the critical value of t as 0.824 < 1.345, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.</em>

<em />

Therefore, we conclude that the mean speed of vehicles is lesser than or equal to 30 miles per hour which means that the county's claim is not supported.

4 0
4 years ago
Mathematical Statistics with Applications Help Homework
Mars2501 [29]

7.43: Let X denote the random variable for height and \overline X for the sample mean. Then if \mu is the mean of

So the probability that the difference between the sample and population means does not exceed 0.5 inch is

P(|\overline X-\mu|\le0.5) = P\left(\left|\dfrac{\overline X-\mu}{0.25}\right|\le\dfrac{0.5}{0.25}\right) = P(|Z|\le 2) \approx \boxed{0.95}

per the empirical or 68/95/99.7 rule.

7.44: For a sample of size <em>n</em>, the sample standard deviation would be \frac{2.5}{\sqrt n}. We want to find <em>n</em> such that

P(|\overline X-\mu| < 0.4) = 0.95

Comparing to the equation from the previous part, this means we would need

\dfrac{0.4}{\frac{2.5}{\sqrt{n}}} = 0.16\sqrt n = 2 \implies \sqrt n = 12.5 \implies n = 156.25

so a sample of at least 157 men would be sufficient.

7 0
3 years ago
Solve for d. 1.2+d+0.4=9.7
Advocard [28]
Move everything around. d+1.6=9.7. d=8.1.
3 0
4 years ago
Read 2 more answers
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