X intercept = -4 y intercept = 2
We are given with the data of a parabola with vertex at (2, 2) and directrix at <span>y = 2.5. the formua should be ax^2 + b x + c = y because of the directrix.
(x-h)^2 = 4a (y-k)
(x-2)^2 =4a (y-2)
a is the equidistant distance from focus to vertex and from vertex to directrix that is equal to -0.5
then the answer is
</span>(x-2)^2 =-0.5*4 (y-2)
<span>x2 - 4x + 4 = -2y +4
x2-4x+2y = 0
answer is C
</span>
Answer:
Bc = √63 ft
Step-by-step explanation:
Here, we want to get the length of BC
As we can see, there is a right angled triangle ABC, with 12ft being the hypotenuse and 9 ft the other side
So we want to get the third leg which is BC
we can use the Pythagoras’ theorem here
And that states that the square of the hypotenuse equals the sum of the squares of the two other sides
let the missing length be x
12^2 = x^2 + 9^2
144 = x^2 + 81
x^2 = 144-81
x^2 = 63
x = √63 ft
Answer:
D
Step-by-step explanation:
your function is not very clear but I'm assuming it's 2 multiplied by 7^x
first let y be equal to the function
to find the range interchange x and y and make the subject
at some point you'll have to use logarithm to get rid of the exponent
only log of positive numbers numbers exist hence y must be greater than 0
