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Tasya [4]
3 years ago
14

Paul paid $ 25.50 for 3 cups of hot chocolate and cups of tea. The cost of each cup of tea was 2/3 the cost of each cup of hoy c

hocolate. How much did each cup of hot chocolate cost?
Mathematics
1 answer:
Allushta [10]3 years ago
7 0

Let the cost of one cup of hot chocolate  be = x

Let the cost of one cup of hot tea be = y

Paul paid $ 25.50 for 3 cups of hot chocolate and 4 cups of tea.

Equation becomes = 3x+4y=25.50   ...(1)

As given, the cost of each cup of tea was 2/3 the cost of each cup of hot chocolate.

y=\frac{2x}{3}   .... (2)

Putting the value of y from (2) in (1)

3x+4(\frac{2x}{3})=25.50

=3x+\frac{8x}{3}=25.50

=\frac{9x+8x}{3}=25.50

=17x=76.5

x=4.5

y=\frac{2x}{3}

=\frac{2*4.5}{3}

y =3

Hence each cup of hot chocolate is $4.50

Each cup of tea is $3.

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<h3>What is a quadratic polynomial?</h3>

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For any given quadratic polynomial we have

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Substituting the values of the variables into the equation, we have

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