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7nadin3 [17]
4 years ago
10

How do I find the domain and range of a graph?​

Mathematics
1 answer:
tia_tia [17]4 years ago
7 0

The domain is the x-axis and the range is the y-axis.

To find the domain, you measure or count the widest part of this oval horizontally. So that is 3 units to the right of 0 and 3 units to the left of 0. I counted it exactly on the axis because that is the widest part of the oval.

To find the range, you again count or measure the widest part of the oval vertically. So that is 4 units above 0 and 4 units below 0.

<u>Final Answer</u>

D: -3 ≤ x ≤ 3

R: -4 ≤ x ≤4

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If AB = x+ 4, BC = 2x -10 and AC
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Answer:

15

Step-by-step explanation:

By the diagram, you can see the sum of segment AB and segment BC is segment AC. Adding the given expressions for AB and B is 3x-6. Simplifying the equation 3x-6=2x+1, gives x=7. Substituting x=7 in the equation for segment AC gives 15.

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The number of ancestors in different generations of a male honeybee follow a Fibonacci sequence in five generations of male hone
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In generation 8 it would have 34 relatives, and in generation 9 it would have 55 relatives.

In the Fibonacci sequence, each term is found by adding the two previous terms together.  For generation 8, we would add generation 7 (21) and generation 6 (13); 21+13 = 34.  For generation 9, we would add generation 8 (34) and generation 7 (21); 34 + 21 = 55.
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3 years ago
What is the measure of the angle formed by the minute hand and the hour hand of a clock when the clock shows 3:00?
FrozenT [24]

Answer: 90 degree angle

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4 0
3 years ago
Read 2 more answers
12x-5y=20 y=x+4<br> 3x+y=3 x=-y+3
Vladimir79 [104]
Standard form (which I assume is what they want you to turn these into) is y=mx+b.

12x-5y=20 is y=2.4x-4.
Subtract 12x from both sides, -5y=-12x+20.
Multiply both sides by -1, 5y=12x-20.
Divide both sides by 5, y=2.4x-4.

y=x+4 is already in standard form- I'm not quite sure what to do.

3x+y=3 is y=-3x+3.
Subtract 3x from both sides, y=-3x+3.

x=-y+3 is y=-x+3
Ad y to both sides, y+x=3.
Subtract x from both sides, y=-x+3.
4 0
3 years ago
Given the vectors, a=3i+4j, b=-2i+5j, c=10i-j, d=-1/3i+5/2j, find -0.4a-0.3b+0.2d=?
sveta [45]

Answer:

-\frac{2}{3}i - \frac{13}{5}j

Step-by-step explanation:

-0.4(3i + 4i) - 0.3(-2i + 5j) + 0.2(-\frac{1}{3}i + \frac{5}{2}j)

-1.2i - 1.6j + 0.6i - 1.5j - \frac{0.2}{3}i + 0.5j

Converting to fraction form;

-\frac{6}{5}i + \frac{3}{5}i - \frac{1}{15}i - \frac{8}{5}j - \frac{3}{2}j + \frac{1}{2} j

<u>Solving the i part;</u>

\frac{-18i + 9i - i}{15} = -\frac{2}{3}i

<u>Solving the j part;</u>

\frac{-16j-15j+5j}{10} = -\frac{13}{5}j

So -0.4a - o.3b + 0.2d =  -\frac{2}{3}i - \frac{13}{5}j

6 0
3 years ago
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