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2 years ago

Use Natural Logarithms to solve the equation

Mathematics

1 answer:

Rus_ich [418]2 years ago

7 0

Answer:

A) 0.106

Step-by-step explanation:

8e^3x + 4 = 15

Subtract 4 from each side

8e^3x + 4-4 = 15-4

8e^3x = 11

Divide each side by 8

8/8e^3x = 11/8

e^(3x) = 11/8

Take the natural log of each side

ln(e^(3x)) = ln(11/8)

3x = ln(11/8)

Divide by 3

3x/3 = 1/3 ln(11/8)

x = 1/3 ln(11/8)

x =.106151244

To the nearest thousandth

x = .106

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How do you do this question?

quester [9]

Step-by-step explanation:

F(x) = ∫ₐˣ t⁷ dt

F(x) is the area under f(t) between t=a and t=x. When x=a, the width of the interval is 0, so the area is zero.

F(6) = 0, so a = 6.

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3 years ago

F - 3/4 = 1/2 what is f?

Julli [10]

Answer:

f=5/4

Step-by-step explanation:

f=1/2+3/4

f=(1/2)×2+3/4

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f=5/4

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3 years ago

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2 years ago

The wait time to ride the thunder boats is 30 minutes when 180 people are in line. Write and solve a proportion to find the wait

mars1129 [50]

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6 0

3 years ago

In an effort to estimate the mean of amount spent per customer for dinner at a major Lawrence restaurant, data were collected fo

larisa86 [58]

Answer:

The 99% confidence interval for the population mean is 22.96 to 26.64

Step-by-step explanation:

Consider the provided information,

A sample of 49 customers. Assume a population standard deviation of $5. If the sample mean is $24.80,

The confidence interval if 99%.

Thus, 1-α=0.99

α=0.01

Now we need to determine $z_{\frac{\alpha}{2}}=z_{0.005}$

Now by using z score table we find that $z_{\frac{\alpha}{2}}=2.58$

The boundaries of the confidence interval are:

$\mu-z_{\frac{\alpha}{2}}\times \frac{\sigma}{\sqrt{n} }\\24.80-2.58\times \frac{5}{\sqrt{49}}=22.96\\\mu+z_{\frac{\alpha}{2}}\times \frac{\sigma}{\sqrt{n} }\\24.80+2.58\times \frac{5}{\sqrt{49}}=26.64$

Hence, the 99% confidence interval for the population mean is 22.96 to 26.64

3 0

3 years ago