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3 years ago

Use Natural Logarithms to solve the equation

Mathematics

1 answer:

Rus_ich [418]3 years ago

7 0

Answer:

A) 0.106

Step-by-step explanation:

8e^3x + 4 = 15

Subtract 4 from each side

8e^3x + 4-4 = 15-4

8e^3x = 11

Divide each side by 8

8/8e^3x = 11/8

e^(3x) = 11/8

Take the natural log of each side

ln(e^(3x)) = ln(11/8)

3x = ln(11/8)

Divide by 3

3x/3 = 1/3 ln(11/8)

x = 1/3 ln(11/8)

x =.106151244

To the nearest thousandth

x = .106

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, list the first five terms of each sequence, and identify them as arithmetic or geometric.

Serhud [2]

Answer:

The first 5 terms are -6,-25,-44,-63 and -82

The sequence is arithmetic

Step-by-step explanation:

Given that A(n + 1) = A(n) − 19 for n ≥ 1 and A(1) = −6

A(1) = -6

A(2) = A(1) − 19 = -6 - 19 = -25

A(3) = A(2) − 19 = -25 - 19 = -44

A(4) = A(3) − 19 = -44 - 19 = -63

A(5) = A(4) − 19 = -63 - 19 = -82

So the first 5 terms are -6,-25,-44,-63 and -82

If they are in arithmetic the common difference will be same, if geometric common ratio will be same.

Let us check common difference,

-25-(-6) = -19

-44-(-25) = -19

-63-(-44) = -19

-82-(-63) = -19

So common difference is same, so the sequence is arithmetic.

3 0

4 years ago

the scale of a map is 1 in :250 miles City A is 378 miles from City B To the nearest tenth how far is its distance on the map

avanturin [10]

1.5 inches. You take 378 and divide it by 250

3 0

4 years ago

Initially, there are 40 grams of A and 50 grams of B, and for each gram of B, 2 grams of A is used. It is observed that 15 grams

hram777 [196]

Answer:

$X(16)=25.71grams$

Step-by-step explanation:

let $X(t)$ denote grams of $C$ formed in $t$ mins.

For $X grams$ of $C$ we have:

$\frac{2}{3}Xg$ of A and $\frac{1}{3}Xg$ of B

Amounts of A,B remaining at any given time is expressed as:

$40-\frac{2}{3}Xg$ of A and $50-\frac{1}{3}Xg$ of B

Rate at which C is formed satisfies:

$\frac{dX}{dt} \infty(40-\frac{2}{3}X)(50-\frac{1}{3}X)->\frac{dX}{dt}=k(90-X)\\\therefore \frac{dX}{(90-X)^2}=kdt->\int{\frac{dX}{(90-X)^2}} \, =\int {k} \, dt \\\therefore \frac{1}{90-X}=kt+c->90-X=\frac{1}{kt+c}\\\\X(t)=90-\frac{1}{kt+c}$

Apply the initial condition, $X(0)=0$ ,to the expression above

$0=90-\frac{1}{c} \ \ ->c=\frac{1}{90}\\\therefore\\X(t)=90-\frac{1}{kt+\frac{1}{90}} \ \ ->X(t)=90-\frac{90}{90kt+c}$

Now at $X(8)=15$ :

$15=90-\frac{90}{90\times 8k+1} \ ->75=\frac{90}{720k+1}\\k=0.0002778$

Substitute in X(t) to get

$X(t)=90-\frac{90}{0.0002778t\times 90+1}\\X(t)=90-\frac{90}{0.25t+1}\\But \ t=16\\\therefore X(t)=90-\frac{90}{0.025\times16+1}\\X(t)=25.71$

5 0

3 years ago

Factor the expression<br> 3x +9 <br>The factored expression is....

muminat

Answer:

i believe it's "(x+3)(x+3)(x+3)" but double check me on that.

5 0

3 years ago

Sam said shape A has a uniform cross section. Lloyd said shape B has a uniform cross section. Who is correct? Explain your answe

STatiana [176]

Answer:

Sam is right. shape A which is cylinder has uniform cross section.

Explanation:

what is uniform cross section?

uniform cross section is when cut through an object and the bases are similar.

solution:

For cylinder:

when we cut a cylinder, its in a circle shaped and have similar bases - thus have uniform cross section.

For pyramid:

when we cut a pyramid it is in rectangle shape and this changes as we go up or down the pyramid and does not have uniform cross section.

4 0

3 years ago

Read 2 more answers