Question

What does the following loop do?int[] a = {6, 1, 9, 5, 12, 3};int len = a.length;int x = 0;for (int i = 1; i < len; i++)if (a[i] > a[x]) x = i;System.out.println(x);1. Finds the position of the largest value in a.2. Sums the elements in a.3. Finds the position of the smallest value in a.4. Counts the elements in a.

Answer 1

Answer:

Option 1: Finds the position of the largest value in a

Explanation:

Given the codes as follows:

1.        int[] a = {6, 1, 9, 5, 12, 3};
2.        int len = a.length;
3.        int x = 0;
4.        for (int i = 1; i < len; i++)
5.        {
6.            if (a[i] > a[x])
7.                x = i;
8.        }
10.        System.out.println(x);

The code is intended to find a largest value in the array, a. The logic is as follows:

• Define a variable to hold an index where largest value positioned. At the first beginning, just presume the largest value is held at index zero, x = 0. (Line 3)
• Next, compare the value location in next index. If the value in the next index is larger, update the index-x to the next index value (Line 4 - 8). Please note the for-loop traverse the array starting from index 1. This is to enable the index-1 value can be compared with index-0 and then followed with index-2, index-3 etc.
• After completion of the for-loop, the final x value will be the index where the largest value is positioned.
• Print the position of the largest value (Line 10)