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elixir [45]
3 years ago
6

How does the team know what to work upon during the iteration

Computers and Technology
1 answer:
Brilliant_brown [7]3 years ago
7 0

Answer:

Based on the discussions during iteration planning, team members agree on what each would work on.

Explanation:

Iteration can be defined as the way in which a process is been repeated in order to generate a possibly outcomes and this occur in a situation where the sequence will approach some end point in which each repetition of the process will be a single iteration while the outcome of each iteration will then be the starting point of the next iteration.

Therefore the team know what to work upon during the iteration Base on the discussions during iteration planning in which the team members agree on what each of them would work on.

During the iteration planning, the team collectively make a decision on how much of the backlog actually they will commit to the iteration in which the committed backlog then is taken to the delivery during the next iteration which is why the goals or objectives of the iteration get determined on the basis of the work committed.

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3 0
3 years ago
In the second example with modulus math, why can't Eve find the solution?
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Answer:

true

Explanation:

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3 years ago
To keep you from inadvertently moving controls as you work in the IDE, click the form or control, then click the _________ optio
Alenkinab [10]

Answer:

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Explanation:

4 0
3 years ago
C++
Nookie1986 [14]

Answer:

Following are the code to the given question:

#include <iostream>//header file

using namespace std;

class Window //defining a class Window

{

private:

int width, height;//defining integer variable

public:

friend ostream& operator << (ostream& stm, Window& width)//defining a friend function that takes two parameters

{

return stm<<"a ("<<width.width<<" x "<<width.height<<") window"; //use return keyword that return its values

}  

Window(int width, int height): width(width), height(height)//defining parameterized constructor that inherit width and height in its parameters  

{}

};

int main() //Main method

{

Window w(80,90);//calling class constructor

cout<<w;//print object value

return 0;

}

Output:

a (80 x 90) window

Explanation:

In the above code, a class "Window" is defined that uses a friend function "ostream& operator" is declared that uses the "ostrea&" as a data type to hold two-variable "stm and w" in its parameter, and declared the parameterized constructor to hold value by inheriting width and height in its parameters.

Inside the main method, a class object is created that calls the constructor and uses the print method to print object value.

7 0
3 years ago
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