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-Dominant- [34]
3 years ago
9

Gabrielle's age is three times Mikhail's age. The sum of their ages is 92. What is Mikhail's age?

Mathematics
1 answer:
Stolb23 [73]3 years ago
6 0

Answer:

Gabrielle is 69 while Mikhail is 23.

Step-by-step explanation:

Let G represent Gabrielle's age and M represent Mikhail's age.

Gabrielle is three times Mikhail's age. In other words:

G=3M

The sum of their ages is 92. In other words:

G+M=92

This is a system of equations. Solve. Substitute in G:

G+M=92\\(3M)+M=92\\4M=92\\M=23

Thus, Mikhail is 23. Now, find Gabrielle's age:

G=3M\\G=3(23)\\G=69

Gabrielle is 69.

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Read 2 more answers
URGENTE, POR FAVOR
Firlakuza [10]
\mathbf A=\begin{bmatrix}a_{1,1}&a_{1,2}\\a_{2,1}&a_{2,2}\end{bmatrix}

a_{i,j}=2i-j\implies\mathbf A=\begin{bmatrix}2\cdot1-1&2\cdot1-2\\2\cdot2-1&2\cdot2-2\end{bmatrix}=\begin{bmatrix}1&0\\3&2\end{bmatrix}

Por la misma razón,

\mathbf B=\begin{bmatrix}1-1&2-1\\1-2&2-2\end{bmatrix}=\begin{bmatrix}0&1\\-1&0\end{bmatrix}

Entonces,

4\mathbf A=\begin{bmatrix}4\cdot1&4\cdot0\\4\cdot3&4\cdot2\end{bmatrix}=\begin{bmatrix}4&0\\12&8\end{bmatrix}

\mathbf A-\mathbf B=\begin{bmatrix}1&0\\3&2\end{bmatrix}-\begin{bmatrix}0&1\\-1&0\end{bmatrix}=\begin{bmatrix}1-0&0-1\\3-(-1)&2-0\end{bmatrix}=\begin{bmatrix}1&-1\\4&2\end{bmatrix}

\mathbf B^\top=(b_{j,i})_{2\times2}=\begin{bmatrix}b_{1,1}&b_{2,1}\\b_{1,2}&b_{2,2}\end{bmatrix}=\begin{bmatrix}0&-1\\1&0\end{bmatrix}

Yo no reconozco la notación "Ae"... Puedes explicarla?

a_{1,1}\cdot b_{1,1}=1\cdot0=0

a_{2,2}\cdot b_{1,2}=2\cdot1=2
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