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TiliK225 [7]
3 years ago
10

How can the properties of linear pairs and vertical angles help to determine the angle measures created by the intersecting line

s?
Mathematics
1 answer:
mafiozo [28]3 years ago
3 0

Answer:

when 2 lines intersect ,4 angles are formed.in that vertically opposite angles will be equal. adjacent angles will be found using linear pair{sum of linear pair of angles will be 180degree}.

Step-by-step explanation:

because

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The new radius is 10.5.
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Which function is represented by this graph?
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6x + 5y = 16<br> −6x + 7y = 80
Kobotan [32]

The equation of the line in point-slope form is equal to

The equation of the line in standard form is equal to

step 1

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3 years ago
Find the equation of a line perpendicular to y - 12 = 2x – 8 that passes through the point (2, 3). (answer in slope-intercept fo
Alla [95]

Answer:

\displaystyle y=-\frac{1}{2}x+4

Step-by-step explanation:

<u>Equation of a Line</u>

We can find the equation of a line by using two sets of data. It can be a pair of ordered pairs, or the slope and a point, or the slope and the y-intercept, or many other combinations of appropriate data.

We are given a line

y - 12 = 2x -8

And are required to find a line perpendicular to that line. Let's find the slope of the given line. Solving for y

y = 2x +4

The coefficient of the x is the slope

m=2

The slope of the perpendicular line is the negative reciprocal of m, thus

\displaystyle m'=-\frac{1}{2}

We know the second line passes through (2,3). That is enough information to find the second equation:

y-y_o=m'(x-x_o)

\displaystyle y-3=-\frac{1}{2}(x-2)

Operating

\displaystyle y=-\frac{1}{2}(x-2)+3

Simplifying

\displaystyle y=-\frac{1}{2}x+4

That is the equation in slope-intercept form. Intercept: y=4

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%2F7%7D%7B7%5Csqrt%7B10%7D%2F2%20%7D" id="TexFormula1" title="\frac{3/7}{7\sqrt{10}
VashaNatasha [74]

Multiply the numerator and denominator by 7×2 = 14 to eliminate the denominators of those fractions:

\dfrac{\dfrac37}{\dfrac{7\sqrt{10}}2}\times\dfrac{14}{14}=\dfrac{3\times2}{7\sqrt{10}\times7}=\dfrac6{49\sqrt{10}}

Rationalize the denominator by multiplying both numerator and denominator by √10:

\dfrac6{49\sqrt{10}}\times\dfrac{\sqrt{10}}{\sqrt{10}}=\dfrac{6\sqrt{10}}{49(\sqrt{10})^2}=\dfrac{6\sqrt{10}}{49\times10}=\dfrac{6\sqrt{10}}{490}

Lastly, cancel the common factor of 2 in both the numerator and denominator (which comes from 6 = 2×3 and 490 = 2×245):

\dfrac{6\sqrt{10}}{490}=\dfrac{3\sqrt{10}}{245}}

8 0
3 years ago
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