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yarga [219]
3 years ago
14

What is the answer to this problem. it must be one of the four choices.

Mathematics
1 answer:
Alenkasestr [34]3 years ago
3 0

The correct answer would be B. 2/(x + 8)

When you are completing composite functions, you place the entire second function in for x in the first function. Since the letter f comes first in f o g. then we start with the f(x) equation.

f(x) = 2/x

Now since g comes next, we take the entire equation for g(x) and substitute it in.

f o g = 2/(x + 8)

This is answer B.

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-5y - 6bStep 1 of 2: Identify the first term of the algebraic expression. Indicate whether theterm is a variable term or a const
ira [324]

Answer:

a. Variable term

b. Variable term

Explanation:

a) We were given the algebraic expression:

-5y-6b

The first term of the algebraic expression is:

-5y

The first term is a variable term

The variable is "y" and its coefficient is "-5"

b) We were given the algebraic expression:

-5y-6b

The second term of the algebraic expression is:

-6b

The second term is a variable term

The variable is "b" and the coefficient is "-6"

6 0
2 years ago
The sample space of a random experiment is {a, b, c, d, e} with probabilities 0.1, 0.1, 0.2, 0.4, and 0.2 respectively. Let A de
antoniya [11.8K]

Answer:

a) P(A) =P(a)+P(b) +P(c)= 0.1+0.1+0.2 = 0.4

b) P(B) =P(c) +P(d)+P(e)=0.2+0.4+0.2=0.8

c) P(A') = 1-P(A) =1-0.4=0.6

d) P(A \cup B) =0.4 +0.8-0.2 =1.0

e)  The intersection between the set A and B is the element c so then we have this:

P(A \cap B) = P(c) =0.2

Step-by-step explanation:

We have the following space provided:

S= [a,b,c,d,e]

With the following probabilities:

P(a) =0.1, P(b)=0.1, P(c) =0.2, P(d)=0.4, P(e)=0.2

And we define the following events:

A= [a,b,c], B=[c,d,e]

For this case we can find the individual probabilities for A and B like this:

P(A) = 0.1+0.1+0.2 = 0.4

P(B) =0.2+0.4+0.2=0.8

Determine:

a. P(A)

P(A) =P(a)+P(b) +P(c)= 0.1+0.1+0.2 = 0.4

b. P(B)

P(B) =P(c) +P(d)+P(e)=0.2+0.4+0.2=0.8

c. P(A’)

From definition of complement we have this:

P(A') = 1-P(A) =1-0.4=0.6

d. P(AUB)

Using the total law of probability we got:

P(A \cup B) =P(A) +P(B)-P(A \cap B)

For this case P(A \cap B) = P(c) =0.2, so if we replace we got:

P(A \cup B) =0.4 +0.8-0.2 =1.0

e. P(AnB)

The intersection between the set A and B is the element c so then we have this:

P(A \cap B) = P(c) =0.2

8 0
3 years ago
What is not an example of kinetic energy?
Anestetic [448]

Answer:

Moving Car. Moving cars possess some amount of kinetic energy. ...

Bullet From a Gun. A bullet fired from a gun has very high kinetic energy, and, so, it can easily penetrate any object. ...

Flying Airplane. ...

Walking & Running. ...

Cycling. ...

Rollercoasters. ...

Cricket Ball.

5 0
3 years ago
Read 2 more answers
Pls help with steps 2 and 4!!! (Will give brainliest)
Natalka [10]

The Answer to your problem is:

#2 Answer:

13x + 7y


#4 Answer:

13x + 7y


I believe it's Distribute

6 0
3 years ago
Penny percent. Suppose you flip a coin 100 times, with 53 tosses landing heads up. What percentage of the tosses would be heads?
timurjin [86]
Percentage of heads
= 53/100 x 100
=53%
percentage of tails
= 100-53
=47
=47/100 x100
= 47%
5 0
3 years ago
Read 2 more answers
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