First get the formula for your pattern in the form of TN. Where d represents your difference and a represents your first term. Then equate the -401 to your formula and solve for n

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2 years ago

A survey reveals that the sales of smartphones is increasing considerably. The average annual sales of smartphones, in million u

padilas [110]

Answer:

C. When the survey was initially conducted average sales of smartphones was 1.7 millions units.

Step-by-step explanation:

We have been given that the average annual sales of smartphones, in million units, n years after the survey is conducted is modeled by function $p(n)=1.7\cdot b^n$ , where the parameter b is an unknown positive base.

We are asked to find the true statement about our given function.

A. If b= 1.45, the annual growth rate of the sales of smartphones is 145%.

Since we know that b equals (1+r) for growth function, where r is in decimal form.

If b=1.45, it means that the annual growth rate will be 45% as 0.45 is decimal form of 45%, therefore, statement A is not true.

B. If b= 1.02, annual sales of smartphones will double in 2 years.

If b=1.02, it means that the annual growth rate will be 2% as 0.02 is decimal form of 2%, therefore, statement B is not true.

C. When the survey was initially conducted average sales of smartphones was 1.7 millions units.

Since we know that an exponential function is in form $y=a*b^x$ , where a in initial value of function. We can see from our given function that a equals 1.7, therefore option C is a true statement.