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Stells [14]
3 years ago
13

Consider the trial on which a 3 is first observed in successive rolls of a six-sided die. Let A be the event that 3 is observed

on the first trial. Let B be the event that at leasttwotrialsarerequiredtoobservea3.Assumingthat each side has probability 1/6,
1. P(A)
2. P(B)
3.P(A U B)
Mathematics
1 answer:
Gwar [14]3 years ago
7 0

Answer:

1) 0.1667

2) 0.8333

3) 1

Step-by-step explanation:

Let A be the event that 3 is observed on the first trial.

Let B be the event that at least two trials are required to observe a 3

a) A six-sided die has 6 possible outcomes of 1,2,3,4,5,6

3 is one of the six possible outcomes

P(A) = no of favourable outcomes /no of possible outcomes

P(A) = 1/6 = 0.1667

b) The event of requiring at least two trials to observe a 3 is the event of not observing a 3 on the first trial.

P(B) = P(A')

P(A')= 1 - P(A)

P(B) = 1 - 1/6

= 5/6 = 0.8333

c) P(AnB) = P(A) + P(B)

= 1/6 + 5/6

= 6/6 = 1

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I don’t understand this!!
Rufina [12.5K]

Answer:

9, 11, 13

Step-by-step explanation:

We can rephrase an odd number into an algebraic equation of (2n+1)

Therefore, 3 consecutive odd numbers would be written as:

(2n+1), (2n+3), (2n+5)

We can then rewrite the question as:

3 x (2n+1) = 2 x (2n+5) + 1

Work out the equation to find n:

6n + 3 = 4n + 10 + 1

(minus 4n from both sides)

2n + 3 = 11

(minus 3 from both sides)

2n = 8

(divide both sides by 2 to get)

n = 4

To find the original 3 consecutive numbers, we just input (4) into (2n+1), (2n+3), (2n+5) to get:

(8+1), (8+3), (8+5)

= 9, 11 and 13

6 0
3 years ago
How do you solve -6(a+8)
algol [13]
Use the distributive property.

This states that: a(b+c)= ab+ac

So,

-6*a= -6a and -6*8= -48

-6a+-48

This is the most you can simplify this problem.

I hope this helps!
~kaikers
4 0
3 years ago
Read 2 more answers
In ΔLMN, m = 390 cm, n = 430 cm and ∠L=134°. Find the length of l, to the nearest centimeter. PLEASE HELP ITS URGENT
BartSMP [9]

Answer:

755

Step-by-step explanation:

DeltaMath

3 0
3 years ago
• a helicopter hovering at 10 m above the ground is shining a spotlight at a person 30 m away1 . if the person is 2 m tall how l
pshichka [43]

As shown in the figure

Height of helicopter above the ground=30 m

Distance from the base to the point where the person is standing=30 m

height of the person=2 m

Now the person cast the shadow of length x m.

Triangle ABC and triangle EDC are similar.

∵ ∠B= ∠D=90°

∠C is common.

So by AA similarity ΔABC and ΔEDC are similar.

As we know when triangles are similar their sides are proportional.

AB/AD =BC/DC

Let DC=x meter

⇒\frac{10}{x}=\frac{30+x}{x}

⇒5=\frac{30+x}{x}[/tex]

⇒5x=30+x

⇒4x = 30

⇒ x=30/4

⇒ x=7.5 meter

So length of shadow=7.5 meter

2. volume of a sphere of radius r is v (r) =\frac{4}{3}π r^{3}

\frac{\mathrm{d} }{\mathrm{d} r}V=4/3π×3r^2

       =4πr^2


surface area of a sphere of radius r is 4πr^2

b)  Ratio of derivative of volume of sphere to surface area of sphere=\frac{4\pi r^2}{4\pi r^2}

             =1  [ incomplete question but you have written few words ]

4 0
2 years ago
Which description can represent the surface area of this trunk
Elina [12.6K]

Answer:

It's B.

Step-by-step explanation:

A trunk has six faces . The total  surface area will be the sum of the areas of these faces.

3 0
3 years ago
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