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Nikitich [7]
3 years ago
7

Brian planted 6 rows of tulip bulbs with 5 bulbs in each row. This is 3 times as many bulbs as Ester planted. How many bulbs did

Ester plant?
Mathematics
1 answer:
Zinaida [17]3 years ago
5 0
6 x 5 = 30
30 ÷ 3 =10
Ester planted 10 bulbs
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A bag contains 150 marbles. Some are blue, and the rest are white. There are 21 blue marbles for every 4 white marbles. How many
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Answer:

are you sure that you have the question right? because this is not do able unless fractions are allowed.

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The director of the library calculates that 29% of the library's collection is checked out. If the director is right, what is th
marusya05 [52]

Answer:

The probability that the proportion of books checked out in a sample of 412 books would differ from the population proportion by less than 4% is P=0.9255.

Step-by-step explanation:

The population's proportion is \pi=0.29

If we take a sample of 412 books (n=412), we have a standard deviation of the sampling distribution of:

\sigma_M=\sqrt{\frac{\pi(1-\pi)}{n}}=\sqrt{\frac{0.29*0.71}{412}}=\sqrt{0.0005} =0.0224

We have to calculate the probabilty that the sample proportion will be between 0.25 and 0.33.

z_1=(0.25-0.29)/0.0224=-0.04/0.0224=-1.7857\\\\z_2=1.7857\\\\\\P(0.25

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3 years ago
Inequality for 3x+1>x-1
Diano4ka-milaya [45]

Answer:

x>-1

Step-by-step explanation:

solve this normally like a linear equation

3x + 1 >x-1

collect like terms

3x-x>-1-1

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Luisa is making a histogram for the following set of data: 11, 77, 35, 5, 76, 34, 89, 92, 22. Which is an appropriate first inte
creativ13 [48]

Answer:

Step-by-step explanation:

The given data is 11, 77, 35, 5, 76, 34, 89, 92, 22

The total number of items in the data is 9. The width of each class interval would be gotten by dividing the difference between the minimum and maximum items in the data by the number of class intervals. From the information given,

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Difference = 92 - 5 = 7

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2 years ago
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Find the error with this proof and explain how it mat be corrected in order to clearly prove the equation.
enyata [817]

Answer:

Step-by-step explanation:

It is true that for any given odd integer, square of that integer will also be odd.

i.e if m is and odd integer then m^{2} is also odd.

In the given proof the expansion for (2k + 1)^{2} is incorrect.

By definition we know,

(a+b)^{2} = a^{2} + b^{2} + 2ab

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Now, we know 4k^{2} and 4k will be even values

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hence (2k + 1)^{2} will be odd, which means m^{2} will be odd.

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3 years ago
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