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Lisa [10]
3 years ago
12

What is the absolute value of the complex number -4- V2/?

Mathematics
1 answer:
Dovator [93]3 years ago
5 0

Answer:

3\sqrt{2}

Step-by-step explanation:

Given the complex number z = a + bi then the absolute value is

| z | = \sqrt{a^2+b^2}

Given - 4 - \sqrt{2} i, then absolute value is

\sqrt{(-4)^2+(-\sqrt{2})^2 }

= \sqrt{16+2}

= \sqrt{18} = \sqrt{9(2)} = 3\sqrt{2}

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I hope that this helps.

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