Question

What is the absolute value of the complex number -4- V2/?

Answer 1

Answer:

3$\sqrt{2}$

Step-by-step explanation:

Given the complex number z = a + bi then the absolute value is

| z | = $\sqrt{a^2+b^2}$

Given - 4 - $\sqrt{2}$ i, then absolute value is

$\sqrt{(-4)^2+(-\sqrt{2})^2 }$

= $\sqrt{16+2}$

= $\sqrt{18}$ = $\sqrt{9(2)}$ = 3$\sqrt{2}$