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2 years ago

What is the absolute value of the complex number -4- V2/?

Mathematics

1 answer:

Dovator [93]2 years ago

5 0

Answer:

3 $\sqrt{2}$

Step-by-step explanation:

Given the complex number z = a + bi then the absolute value is

| z | = $\sqrt{a^2+b^2}$

Given - 4 - $\sqrt{2}$ i, then absolute value is

$\sqrt{(-4)^2+(-\sqrt{2})^2 }$

= $\sqrt{16+2}$

= $\sqrt{18}$ = $\sqrt{9(2)}$ = 3 $\sqrt{2}$

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Hello,

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