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Kamila [148]
3 years ago
9

Please help with my math homework ​

Mathematics
2 answers:
kkurt [141]3 years ago
7 0

Answer: fifty times five

zhuklara [117]3 years ago
4 0

Answer:

approximately 1,000,000,000 leaves.

Step-by-step explanation:

first, calculate the number of leaves on each tree during its lifespan.

10⁵ = 100,000

2 x 100,000 = 200,000

each tree will have 200,000 leaves in its life span.

next, calculate the number of trees in a large forest.

10³ = 1,000

5 x 1,000 = 5,000

a large forest will have about 5,000 trees.

last, multiply the number of leaves per tree by the number of trees to get the number of leaves that grow on the trees in the forest during the lifespan of the trees.

200,000 x 5,000 = 1,000,000,000

there will be approximately 1,000,000,000 leaves on the trees in the forest during their lifespans.

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Help please thanks<br> Xxxxx
lions [1.4K]

Answer:

C

Step-by-step explanation:

are you sure that this is Middle School it seems like Elementary -_-

4 0
3 years ago
For each level of precision, find the required sample size to estimate the mean starting salary for a new CPA with 95 percent co
Rzqust [24]

Answer:

(a) Margin of error ( E) = $2,000 , n = 54

(b)   Margin of error ( E) = $1,000 , n = 216

(c)   Margin of error ( E) = $500 , n= 864

Step-by-step explanation:

Given -

Standard deviation \sigma = $7,500

\alpha = 1 - confidence interval = 1 - .95 = .05

Z_{\frac{\alpha}{2}} =  Z_{\frac{.05}{2}} = 1.96

let sample size is n

(a) Margin of error ( E) = $2,000

Margin of error ( E)  = Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}

                           E   = Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}

Squaring both side

E^{2} = 1.96^{2}\times\frac{7500^{2}}{n}

n =\frac{1.96^{2}}{2000^{2}} \times 7500^{2}

n =  54.0225

n = 54 ( approximately)

(b)   Margin of error ( E) = $1,000

          E     = Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}

         1000   =  Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}

Squaring both side

1000^{2} = 1.96^{2}\times\frac{7500^{2}}{n}

n =\frac{1.96^{2}}{1000^{2}} \times 7500^{2}

n = 216

(c)   Margin of error ( E) = $500

   E = Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}

  500 = Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}

Squaring both side

500^{2} = 1.96^{2}\times\frac{7500^{2}}{n}

n =\frac{1.96^{2}}{500^{2}} \times 7500^{2}

n = 864

7 0
4 years ago
Drop your ig's i need new friends ( high schoolers only)
Luba_88 [7]

Answer:

sorry im middle school we can still hang though

Step-by-step explanation:

8 0
3 years ago
What is the maximum number of real distinct roots that a quartic equation can have?
choli [55]
An nth degree<span> polynomial can have as many as n real roots.</span>
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3 years ago
(4-9-8)÷3×3please help AFAP​
Elenna [48]

Answer:

I am not really sure but try this -13/9 or -13 divided by 9

Step-by-step explanation:

7 0
3 years ago
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