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Kamila [148]
3 years ago
9

Please help with my math homework ​

Mathematics
2 answers:
kkurt [141]3 years ago
7 0

Answer: fifty times five

zhuklara [117]3 years ago
4 0

Answer:

approximately 1,000,000,000 leaves.

Step-by-step explanation:

first, calculate the number of leaves on each tree during its lifespan.

10⁵ = 100,000

2 x 100,000 = 200,000

each tree will have 200,000 leaves in its life span.

next, calculate the number of trees in a large forest.

10³ = 1,000

5 x 1,000 = 5,000

a large forest will have about 5,000 trees.

last, multiply the number of leaves per tree by the number of trees to get the number of leaves that grow on the trees in the forest during the lifespan of the trees.

200,000 x 5,000 = 1,000,000,000

there will be approximately 1,000,000,000 leaves on the trees in the forest during their lifespans.

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Baxter is thinking about buying a car. The table below shows the projected value of two different cars for three years.
saw5 [17]

Car 1: It is an exponential function that is given as P = 18,500 (0.9595)ⁿ and the price after 10 years is $12,235.5.

Car 2: It is a linear function that is given as 2000x + 3y = 55500 and the price after 10 years is $11,833.33.

And Yes, there is a significant difference.

<h3>What is a function?</h3>

A function is a statement, rule, or law that establishes the connection between two variables. In mathematics, functions are everywhere and are necessary for constructing physical connections.

Baxter is thinking about buying a car. The table below shows the projected value of two different cars for three years.

Car 1 (value in dollars)

Year 1: 18,500

Year 2: 17,390

Year 3: 16,346.60

Car 2 (value in dollars)

Year 1: 18,500

Year 2: 17,500

Year 3: 16,500

The exponential function describes car 1.

Then the function will be

\rm P = 18500\times (0.95995)^n

The linear function describes car 2.

\rm y \ - \ 18500 = \dfrac{-2000}{3}(x - 0)\\\\\\3y - 55500 = -2000x\\\\\\2000x +3y = 55500

Then the value of the car 1 after 10 years will be

\rm P = 18500\times (0.95995)^{10}\\\\\\P = \$ \ 12,235.5

Then the value of the car 2 after 10 years will be

\rm 2000 \times 10 +3y = 55500\\\\y =  \$ \ 11,833.33

Yes, there is a significant difference.

More about the function link is given below.

brainly.com/question/5245372

#SPJ1

5 0
2 years ago
The coordinates of A, B, and C in the diagram are A (p, 4), B (6, 1 ), and C (9, q). Which equation correctly relates p and q? ↔
aivan3 [116]

Answer:

  D.  p + q = 7

Step-by-step explanation:

The slope of AB is ...

  mAB = (y2 -y1)/(x2 -x1) = (1 -4)/(6 -p) = -3/(6 -p)

The slope of BC is ...

  mBC = (q -1)/(9 -6) = (q -1)/3

We want the product of these slopes to be -1:

  mAB·mBC = -1 = (-3/(6 -p))·((q -1)/3)

  -(q-1)/(6 -p) = -1 . . . . cancel factors of 3

  q -1 = 6 -p . . . . . multiply by -(6 -p)

  q + p = 7 . . . . . matches choice D

8 0
3 years ago
Given the sequence 1/2 ; 4 ; 1/4 ; 7 ; 1/8 ; 10;.. calculate the sum of 50 terms
miv72 [106K]

<u>Hint </u><u>:</u><u>-</u>

  • Break the given sequence into two parts .
  • Notice the terms at gap of one term beginning from the first term .They are like \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8} . Next term is obtained by multiplying half to the previous term .
  • Notice the terms beginning from 2nd term , 4,7,10,13 . Next term is obtained by adding 3 to the previous term .

<u>Solution</u><u> </u><u>:</u><u>-</u><u> </u>

We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,

\implies S_1 = \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8} .

We can see that this is in <u>Geometric</u><u> </u><u>Progression </u> where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,

\implies S_1 = a\dfrac{1-r^n}{1-r} \\\\\implies S_1 = \dfrac{1}{2}\left[ \dfrac{1-\bigg(\dfrac{1}{2}\bigg)^{25}}{1-\dfrac{1}{2}}\right]

Notice the term \dfrac{1}{2^{25}} will be too small , so we can neglect it and take its approximation as 0 .

\implies S_1\approx \cancel{ \dfrac{1}{2} } \left[ \dfrac{1-0}{\cancel{\dfrac{1}{2} }}\right]

\\\implies \boxed{ S_1 \approx 1 }

\rule{200}2

Now the second sequence is in Arithmetic Progression , with common difference = 3 .

\implies S_2=\dfrac{n}{2}[2a + (n-1)d]

Substitute ,

\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}

Hence sum = 908 + 1 = 909

7 0
3 years ago
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