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tatuchka [14]
3 years ago
11

Question 14 LAST ONE will mark as BRAILEST

Mathematics
2 answers:
Delicious77 [7]3 years ago
5 0

Answer: C

Step-by-step explanation:

rodikova [14]3 years ago
4 0
The answer is indeed c
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Need help to answer
Korolek [52]
Remember, you can do anything to an equation as long as you do it to both sides

times 4 both sides because we hate fractions
3x+8=16x-4
minus 3x both sides
8=13x-4
add 4 both sides
12=13x
divide both sides by 13
12/13=x
x=12/13
4 0
3 years ago
This is giving me a hard time
kirill [66]

Answer:

x= 9,-2

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Consider the differential equation
Ainat [17]

Answer:

W\left ( e^{\frac{x}{2}},xe^{\frac{x}{2}} \right )=e^x

Step-by-step explanation:

Let y=e^{\frac{x}{2}}

Differentiate with respect to x

y'=\frac{1}{2}e^{\frac{x}{2}}

Differentiate with respect to x

y''=\frac{1}{4}e^{\frac{x}{2}}

Put values of y,y',y'' in 4y''-4y'+y=0

4y''-4y'+y=0\\4\left (\frac{1}{4}e^{\frac{x}{2}}  \right )-4\left (  \frac{1}{2}e^{\frac{x}{2}}\right )+e^{\frac{x}{2}}\\=e^{\frac{x}{2}}-2e^{\frac{x}{2}}+e^{\frac{x}{2}}\\=2e^{\frac{x}{2}}-2e^{\frac{x}{2}}\\=0

So, y=e^{\frac{x}{2}} is the solution of the given equation.

Now, let y=xe^{\frac{x}{2}}

Differentiate with respect to x

y'=e^{\frac{x}{2}}+\frac{x}{2}e^{\frac{x}{2}}=e^{\frac{x}{2}}\left ( 1+\frac{x}{2} \right )

Differentiate with respect to x

y''=\frac{1}{2}e^{\frac{x}{2}}+\frac{1}{2}e^{\frac{x}{2}}\left ( 1+\frac{x}{2} \right )=e^{\frac{x}{2}}+\frac{1}{4}xe^{\frac{x}{2}}

Put values of y,y',y'' in 4y''-4y'+y=0

4y''-4y'+y=0\\4\left (e^{\frac{x}{2}}+\frac{1}{4}xe^{\frac{x}{2}}  \right )-4\left (  e^{\frac{x}{2}}\left ( 1+\frac{x}{2} \right )\right )+xe^{\frac{x}{2}}\\=4e^{\frac{x}{2}}+xe^{\frac{x}{2}}-2e^{\frac{x}{2}}(2+x)+xe^{\frac{x}{2}}\\=4e^{\frac{x}{2}}+xe^{\frac{x}{2}}-4e^{\frac{x}{2}}-2xe^{\frac{x}{2}}+xe^{\frac{x}{2}}\\=0

To find: W\left ( e^{\frac{x}{2}},xe^{\frac{x}{2}} \right )

Solution:

Let u=e^{\frac{x}{2}}\,,\,v=xe^{\frac{x}{2}}

W(u,v)=\left | \begin{matrix}u&v\\u'&v' \end{matrix} \right |\\=\left | \begin{matrix}e^{\frac{x}{2}}&xe^{\frac{x}{2}}\\\frac{1}{2}e^{\frac{x}{2}}&e^{\frac{x}{2}}\left ( 1+\frac{x}{2} \right ) \end{matrix} \right |\\=e^{\frac{x}{2}}\left [ e^{\frac{x}{2}}\left ( 1+\frac{x}{2} \right ) \right ]-\frac{1}{2}e^{\frac{x}{2}}xe^{\frac{x}{2}}\\=e^x\left ( 1+\frac{x}{2} \right )-\frac{1}{2}xe^x\\=e^x+\frac{1}{2}xe^x-\frac{1}{2}xe^x\\=e^x

5 0
3 years ago
In a certain town, 42% of voters favor a given ballot measure. For groups of 30 voters, find the
alex41 [277]

Answer:

7.3  voters

Step-by-step explanation:

This scenario follows a binomial distribution with the probability of success (voting in favor of the ballot) p =0.42, and the probability of failure (voting against the ballot), p-1 = 0.58. If the number of events is n=30. The variance is given by:

V= n*p*(1-p)\\V= 30*0.42*(1-0.42)\\V=7.3\ voters

The variance for the number who favor the measure is 7.3 voters.

6 0
3 years ago
Are these angles Supplementary or Complementary
gregori [183]

Answer:

they are suplementary

Step-by-step explanation:

because no right angle and less then 90 degrees

7 0
3 years ago
Read 2 more answers
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