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3 years ago

What are all the subsets of the set {-2,2}

Mathematics

1 answer:

notka56 [123]3 years ago

8 0

When you mean -2+2,than it is 0

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(7m+6) (6m^2+4m+4) I really suck at math

Ostrovityanka [42]

$\large\mathfrak{{\pmb{\underline{\orange{Your\:answer }}{\orange{:}}}}}$

$:⟼ (7m + 6)(6 {m}^{2} + 4m + 4)$

$:⟼ 7m \: (6 {m}^{2} + 4m + 4) + 6 \: (6 {m}^{2} + 4m + 4)$

$:⟼ 42 {m}^{3} + 28 {m}^{2} + 28m + 36 {m}^{2} +24 m + 24$

$:⟼ 42 {m}^{3} + 28 {m}^{2} + 36 {m}^{2} + 28m + 24m + 24$

$:⟼ 42 {m}^{3} + 64 {m}^{2} + 52m + 24$

$:⟼ 2(21 {m}^{3} + 32 {m}^{2} + 26m + 12)$

$\sf \bf {\boxed {\mathbb {HAPPY\:LEARNING.}}}$

3 0

2 years ago

Read 2 more answers

Write your answer (168 ÷ 7) × 3^2 - 43

wolverine [178]

Answer:

173

Step-by-step explanation:

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2 years ago

Read 2 more answers

The response to a question has three alternatives: A, B, and C. A sample of 120 responses provides 60 A, 12 B, and 48 C. Show th

zimovet [89]

Answer:

CLASS FREQUENCIES RELATIVE FREQUENCIES

A 60 0.5

B 12 0.1

C 48 0.4

TOTAL 120 1

Step-by-step explanation:

Given that;

the frequencies of there alternatives are;

Frequency A = 60

Frequency B = 12

Frequency C = 48

Total = 60 + 12 + 48 = 120

Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;

Relative Frequency A = Frequency A / total = 60 / 120 = 0.5

Relative Frequency B = Frequency B / total = 12 / 120 = 0.1

Relative Frequency C = Frequency C / total = 48 / 120 = 0.4

therefore;

CLASS FREQUENCIES RELATIVE FREQUENCIES

A 60 0.5

B 12 0.1

C 48 0.4

TOTAL 120 1

5 0

2 years ago

The area of a square garden is 50 m3. How long is the diagonal?

katen-ka-za [31]

Answer:

10 m

Step-by-step explanation:

If the area of a square is 50 m2, then the length of each side will be $\sqrt{50}$ m, to get the diagonal length, after dividing the square by joining the points of the diagonal with a line, it forms two right angles with length $\sqrt{50}$ m each.

the diagonal length represent the hypotenuse side of each of the right angle, knowing the pythagoras theorem:

$(hyp)^{2} = (opp)^{2} + (Adj)^{2}$ , so we have:

$(diagonal)^{2} = 50 + 50$

$(diagonal)^{2} = 100$

diagonal = 10 m

6 0

3 years ago

Pleaseeee helpppp!!!!

kondor19780726 [428]

The right answer is Option A: $x=\frac{rs-t}{2}$

Step-by-step explanation:

Given expression is;

$s=\frac{2x+t}{r}$

We will solve this expression for x, therefore,

Multiplying both sides by r

$r*s=\frac{2x+t}{r}*r\\rs=2x+t$

Subtracting t from both sides

$rs-t=2x+t-t\\rs-t=2x\\2x=rs-t$

Dividing both sides by 2

$\frac{2x}{2}=\frac{rs-t}{2}\\x=\frac{rs-t}{2}$

The right answer is Option A: $x=\frac{rs-t}{2}$

Keywords: subtraction, division

Learn more about subtraction at:

#LearnwithBrainly

7 0

3 years ago