Answer:
The first four terms of the sequence are-6, -2, 2 and 6
Step-by-step explanation:
The given sequence is 
In order to find the first four term of the sequence we put n =0, 1, 2 and 3.
For n =0

For n =1

For n =2

For n =3

Therefore, the first four terms of the sequence are
-6, -2, 2 and 6
A(-7,-4) B(-2,0)
√[(x'-x)^2+(y'-y)^2]
√(-2-(-7)^2+(0-(-4)^2
√(5^2)+(4^2)
√25+16
√41
the distance is approximately 6.4 units
So if the main question is 9q x 3 it would equal 27q
Answer:
y=-5/6x-5
Step-by-step explanation:
0-(-5)/-6-0
-5/6 slope
y-(-5)=-5/6(x-0)
y+5=-5/6x
y=-5/6x-5
Answer:
9:04
Step-by-step explanation:
21 - 17 = 4
it's using subtraction