Answer:
1 second = 11%
2 seconds = 22%
45 × .22 = 9.9
answer: 9.9 meters
Step-by-step explanation:
Can u repeat the question like the entire question or is that it
Answer:
Number 2 is incorrect
Step-by-step explanation:
The correct answer would be line CA is congruent to line ZX
Answer:
(A) 0.11
(B) 0.0526
(C) Related
(D) 0.28
Step-by-step explanation:
The data provided is:
DC = event that a randomly selected driver is using a cell phone
TA = event that a randomly selected driver has a traffic accident
(A)
From the provided data:
P (DC) = 0.11
(B)
From the provided data:
P (TA) = 0.0526
(C)
To determine whether the events DC and TA are dependent, we need to show that:
![P(DC\cap TA)\neq P(DC)\times P(TA)](https://tex.z-dn.net/?f=P%28DC%5Ccap%20TA%29%5Cneq%20P%28DC%29%5Ctimes%20P%28TA%29)
The value of P (DC ∩ TA) is,
![P(DC\cap TA)=P(DC|TA)\time P(TA)](https://tex.z-dn.net/?f=P%28DC%5Ccap%20TA%29%3DP%28DC%7CTA%29%5Ctime%20P%28TA%29)
![=0.28\times 0.0526\\=0.014728](https://tex.z-dn.net/?f=%3D0.28%5Ctimes%200.0526%5C%5C%3D0.014728)
Now compute the value of P (DC) × P (TA) as follows:
![P (DC) \times P (TA)=0.11\times 0.0526=0.005786](https://tex.z-dn.net/?f=P%20%28DC%29%20%5Ctimes%20P%20%28TA%29%3D0.11%5Ctimes%200.0526%3D0.005786)
So, ![P(DC\cap TA)\neq P(DC)\times P(TA)](https://tex.z-dn.net/?f=P%28DC%5Ccap%20TA%29%5Cneq%20P%28DC%29%5Ctimes%20P%28TA%29)
Thus, cell phone use while driving and traffic accidents are related.
(D)
The probability that the driver was distracted by a cell phone given that the driver has an accident is:
P (DC | TA) = 0.28