Answer:
Hello dear,
Your question is not complete, please paste it complete for better understanding.
Anyhow what i understood from the question, the answer is in the explanation.
Step-by-step explanation:
The mean time between arrivals is 3 minutes. Or else, depending on the way the exponential distribution has been introduced to you, the rate is 1/3.
Recall that an exponential distribution with parameter λ has mean 1λ. So 1λ=3 and therefore λ=13.
A customer has just arrived. Let X be the waiting time until the next customer arrives. Then X has exponential distribution with parameter λ=13. For any positive x,
Pr(X≤x)=∫x013e−t/3dt=1−e−x/3.(1)
Now we can answer the questions. Interpretation is needed, since there are some ambiguities in the questions.
Interpret the question as saying: "Customer Alicia has just arrived. What is the probability that there will be a customer who arrives later than Alicia, but no more than 3 minutes later." Then we want Pr(X≤3) . By (1), this is 1−e−3/3.
Interpret the question as saying that Alicia has just arrived, and we want the probability that there will be a gap of at least 6 minutes until the next customer arrives. Then we want
Pr(X>6) = 1−Pr(X≤6),
which is 1−(1−e−6/3).
