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Fed [463]
3 years ago
6

The SAS Similarity Theorem states that if an angle of one triangle is

Mathematics
2 answers:
Lostsunrise [7]3 years ago
7 0

Answer:

The word is similar

MaRussiya [10]3 years ago
3 0

Answer:

congruent

Step-by-step explanation:

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2,653 rounded to the nearest hundred
meriva

Answer: 2700 because the 5 in the tens place makes you round up

Step-by-step explanation:

6 0
3 years ago
How do I find the n in A=P(1+(r/n)^(nt)?
dmitriy555 [2]
This is the formula for compounded interest.
P is the principal investment,
r is the rate (6%=0.06)
n is the number of times compounded per year (n=12 is monthly, n=2 is twice per year)
T is the number of years past
And A is the amount of money after t years with a rate r compounded n times per year staring at P amount
Final answer:
n is the number of times per year the interest is compounded.
Hope I helped, and sorry it took this long for you to get an answer.
3 0
4 years ago
Solve the inequality -8x < 32
deff fn [24]

Answer:

x>-4

Step-by-step explanation:

-8x<32       -       First isolate the x by dividing both sides by -8

-8x/-8<32/-8      

x>-4

<h2><u>When you divide or multiply by a negative the inequality sign flips.</u></h2>

<u></u>

4 0
3 years ago
Read 2 more answers
Tell whether each pair of angle measurements are complementary, supplementary, or neither: 67°, 105°
ahrayia [7]

Answer:

Review the basics of complementary and supplementary angles, and try some practice problems. ... None of the above. Explain ... Practice set 2: Find a missing angle measure ... How do you tell which angle is which? Reply ... If you can be more specific with what you need assistance for I will be glad to walk you through it :).

Step-by-step explanation:

if  not sorry have a great day or night

6 0
3 years ago
The functions $f$ and $g$ are defined as follows: \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\quad\text{and}\quad g(x) = \dfrac{\sqrt{x+1}}
CaHeK987 [17]

Answer:

The answer is "domain and range are different".

Step-by-step explanation:

Given:

f(x) = \sqrt{\frac{x+1}{x-1}}\\\\g(x) =\frac{\sqrt{x+1}}{\sqrt{x-1}}\\

Solve f(x) to find domain and range:

for element x: R:

⇒ x \leq -1 \ \ \ and \  \ \  x > 1 range:

for  \ \ f(x) \times element : 0 \leq f(x)< 1 \ \ \ or \ \ f(x)>1

g(x) =\frac{\sqrt{x+1}}{\sqrt{x-1}}\\

Solve for domain:

⇒ \ when \ x \ element \ R: \ \ \ x>1  

Solve for range:  

⇒ g(x) \times element  R : g(x)>1

So, the value of the method f(x) and g(x) (range and domain) were different.  

5 0
3 years ago
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