Answer:
The sample size 'n' = 72,030
Step-by-step explanation:
<u>Step(i):-</u>
<em>Given that the Estimate Error = 0.013</em>
<em>Given that the standard deviation of the Population = 1.5</em>
<em>The estimated error is determined by </em>
<em />
<em />
<u><em>Step(ii):-</em></u>
<em>Given that the Level of significance = 0.98 or 0.02</em>
<em>Z₀.₀₂ = 2.326</em>
<em>The estimated error is determined by </em>
<em> </em><em />
<em> </em>
<em />
<em> </em>
<em />
<u><em>Squaring on both sides, we get</em></u>
<em> n = 72,030</em>
<u><em>Final answer:-</em></u>
The sample size 'n' = 72,030
We know that
<span>ρ = density of gasoline = 737 kg/m³ (at T = 60°F = 15.6°C)
</span>ρ = m/V
ρV = m
V = m/ρ
V = 49.0 kg / 737 kg/m³
<span>V = 0.066 m³
[volume of the tank]=L*W*H-----> H=volume/[L*W]----> H=0.066/(0.9*0.4)
H=0.1833 m
the answer is
t</span><span>he depth of the tank is 0.18 m</span>
Answer:
110 test
Step-by-step explanation:
Let
x ----> the number of packet of 10 test
y ----> the total cost
we know that
The number of packet of 10 test purchase multiplied by $11 plus the enrollment fee of $30 must be equal to $151
so
The linear equation that represent this scenario is
we have
substitute
Solve for x
subtract 30 both sides
Divide by 11 both sides
The number of packets purchase was 11
To find out the number of test, multiply the number of packets by 10
We are tasked to solve the value of p(8a) in the expression p(x)=3x^2-4.
This means that what would find the value of the expression when x=8a. To solve this, we simply substitute the value of x in the expression.
p(x)=3x^2-4
p(8a)=3(8a)^2-4
p(8a)=3(64a^2)-4
p(8a)=192a^2-4
