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Firdavs [7]
3 years ago
7

The equation of the line that passes through (1, 8) and (2, 13) is y =5x+3.

Mathematics
1 answer:
emmasim [6.3K]3 years ago
8 0

Answer:

True

Step-by-step explanation:

y=5x+3

8=5(1)+3

13=5(2)+3

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Given that a/b = 3/5 and b/c = 4/5<br> Find a:b:c
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Answer:

12:20:25

I thnk this is it. I'm not sure though

6 0
2 years ago
Evaluate the limit of lim/n-&gt;infinity 6n^2+5/3n^2
castortr0y [4]

we are given

\lim_{n \to \infty} \frac{6n^2+5}{3n^2}

we can see that

degree of numerator = degree of denominator =2

so, we can divide both numerator and denominator by n^2

and we get

\lim_{n \to \infty} \frac{(6n^2+5)/n^2}{(3n^2/n^2)}

\lim_{n \to \infty} \frac{(6n^2/n^2)+(5/n^2)}{(3n^2/n^2)}

now, we can simplify it

\lim_{n \to \infty} \frac{6+(5/n^2)}{3}

now, we can plug n=inf

=  \frac{6+(5/(\infty))}{3}

=  \frac{6+0}{3}

=  \frac{6}{3}

=  2...............Answer

6 0
3 years ago
Read 2 more answers
There is three fourths of a box of cereal remaining. You eat 2/5 of the remaining cereal. What fraction of the box do you eat
likoan [24]
You would eat 3/10 of the box because 3/4 times 2/5 is 3/10. Whenever you see the word "of" it means multiplication.
3 0
3 years ago
Harlene tosses two number cubes. If a sum of 8 or 12 comes up, she gets 9 points. If not, she loses 2 points. What is the expect
Amanda [17]
P(8 or 12) = 1/6
P(not 8 or 12 = 5/6
Let the expected points fro one roll be X.
E(X)=9\times\frac{1}{6}-2\times\frac{5}{6}=-\frac{1}{6}\ points
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5 0
3 years ago
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a gift shop sells 160 wind chimes per month at $150 each. the owners estimate that for each $15 increase in price, they will sel
adell [148]

Answer:

The price per wind chime that will maximize revenue = $ 315

Step-by-step explanation:

Given - A gift shop sells 160 wind chimes per month at $150 each. the owners estimate that for each $15 increase in price, they will sell 5 fewer wind chimes per month.

To find - Find the price per wind chime that will maximize revenue.

Proof -

Given that,

Total Wind chimes selling = 160

Price of each Wind chime = $150

Now,

Given that, for each $15 increase in price, they will sell 5 fewer wind chimes per month.

So,

Let the price = 150 + 15x

So,

Number of wind Chimes sold per month = 160 - 5x

So,

Total Revenue, R = (150 + 15x)(160 - 5x)

                             = 24000 - 750x + 2400x - 75x²

                             = 24000 + 1650x - 75x²

⇒R(x) = 24000 + 1650x - 75x²

Differentiate R with respect to x , we get

R'(x) = 1650 - 150x

Now,

For Maximize Revenue, Put R'(x) = 0

⇒1650 - 150x = 0

⇒150x = 1650

⇒x = 1650/150

⇒x = 11

∴ we get

Price per Wind chime = $ 150 + 15(11)

                                    = $ 150 + 165

                                    = $ 315

So,

The price per wind chime that will maximize revenue = $ 315

3 0
3 years ago
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