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rusak2 [61]
3 years ago
7

Have vehicles gotten more fuel-efficient over the years? Between 1960 and 1999 the size and shape of automobiles in the United S

tates has changed almost annually. The amount of fuel consumed by these vehicles has also changed. The following table describes the average fuel consumption per year per passenger car in gallons of gasoline.
Year, t 1960 1970 1980 1990 1995 1997 1998 1999
Gallons Consumed Per Passenger Car
668
760
576
520
530
538
544
552

Determine the average rate of change, in gallons of fuel used per passenger car, from 1960 to 1970.
Mathematics
2 answers:
slava [35]3 years ago
7 0

Answer:

9.20 gallons of fuel used per passenger car.

Step-by-step explanation:

The given table shows average fuel consumption per year per passenger of fuel consumed by the vehicles in United States.

We have to determine the average rate of change in gallons of used per passenger car between 1960 to 1970.

On a graph average rate of change, of fuel used per passenger car

= \frac{\text{Gallons of fuel used}}{\text{Number of years}}

= \frac{(760-668)}{1970-1960}=\frac{92}{10}=9.20

Therefore, answer is 9.20 gallons of fuel used per passenger car.

Angelina_Jolie [31]3 years ago
5 0
Average rate of change is the slope of two coordinate points or values.
Therefore,
Given values are : 
(1960,668) and (1970,760)
Slope = (760 - 668)/(1970 - 1960)
Slope = 92/10
Rate of change will be 9.2 gallons/passenger
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You have a $3175 student loan. Suppose you pay the loan off in two and a half years (30 months). Estimate your monthly payment b
finlep [7]

Answer:

$106

Step-by-step explanation:

The formula given for Monthly payment of a loan =

P × [ r (1 + r)/(1 + r)^n - 1

Where

r = interest rate

n = number of monthly payments

P = Present value of the loan

From the question,

r = interest rate, we were told to ignore hence, r = 0

P = $3,175

n = 30

Hence,

Amount to be paid monthly = P/n

= $3175/30

= $105.83

Approximately to the nearest dollars

= $106

6 0
3 years ago
Let $a$ and $b$ be nonzero real numbers such that
algol [13]
<h3>Answer:   -7/2</h3>

=========================================================

Explanation:

Let's expand out (2 - 7i)(a + bi) using the FOIL rule

(2 - 7i)(a + bi) = 2a + 2bi - 7ai - 7bi^2

(2 - 7i)(a + bi) = 2a + 2bi - 7ai - 7b(-1)

(2 - 7i)(a + bi) = 2a + 2bi - 7ai + 7b

(2 - 7i)(a + bi) = (2a+7b) + (2bi-7ai)

(2 - 7i)(a + bi) = (2a+7b) + (2b-7a)i

We're told the result is purely imaginary. What this means is that the real part (2a+7b) is zero, while the imaginary part (2b-7a) is nonzero. If both are zero, then we have 0+0i = 0 which is purely real.

For example, the complex numbers 0-7i and 0+2i are purely imaginary.

Let's use the fact that 2a+7b must be zero to do the following steps:

2a+7b = 0

2a = -7b

a = -7b/2

a/b = -7/2 which is the final answer

We must check to see if 2b-7a is nonzero

2b - 7a = 2b - 7(-7b/2)

2b - 7a = 2b + 24.5b

2b - 7a = 26.5b

The result is nonzero if and only if b is nonzero. Luckily we're told b is nonzero at the top of the problem. So we don't have any worries that (2b-7a) is zero.

Therefore, (2a+7b) + (2b-7a)i will be purely imaginary with a/b = -7/2

------------------

A concrete example:

Let a = -14 and b = 4

a/b = -14/4 = -7/2

(2-7i)(a+bi) = (2-7i)(-14+4i) = 0 + 106i which is purely imaginary.

I'll let you do the steps in expanding that out using the FOIL rule.

4 0
1 year ago
What is 2(x+14)+(2x-14
lawyer [7]
2x+28+2x-14
————————
4x+14
5 0
3 years ago
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emmainna [20.7K]

Answer:(0,4), (-1,0), (-4,-2)

Step-by-step explanation:

5 0
3 years ago
Dilation ( effects of changing dimensions on perimeter and area)
Archy [21]
The answer is C) 64in.
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