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rusak2 [61]
3 years ago
7

Have vehicles gotten more fuel-efficient over the years? Between 1960 and 1999 the size and shape of automobiles in the United S

tates has changed almost annually. The amount of fuel consumed by these vehicles has also changed. The following table describes the average fuel consumption per year per passenger car in gallons of gasoline.
Year, t 1960 1970 1980 1990 1995 1997 1998 1999
Gallons Consumed Per Passenger Car
668
760
576
520
530
538
544
552

Determine the average rate of change, in gallons of fuel used per passenger car, from 1960 to 1970.
Mathematics
2 answers:
slava [35]3 years ago
7 0

Answer:

9.20 gallons of fuel used per passenger car.

Step-by-step explanation:

The given table shows average fuel consumption per year per passenger of fuel consumed by the vehicles in United States.

We have to determine the average rate of change in gallons of used per passenger car between 1960 to 1970.

On a graph average rate of change, of fuel used per passenger car

= \frac{\text{Gallons of fuel used}}{\text{Number of years}}

= \frac{(760-668)}{1970-1960}=\frac{92}{10}=9.20

Therefore, answer is 9.20 gallons of fuel used per passenger car.

Angelina_Jolie [31]3 years ago
5 0
Average rate of change is the slope of two coordinate points or values.
Therefore,
Given values are : 
(1960,668) and (1970,760)
Slope = (760 - 668)/(1970 - 1960)
Slope = 92/10
Rate of change will be 9.2 gallons/passenger
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runners in a marathon are randomly assigned to one of ten corrals to start, and each given a green, blue, or red shirt to wear.​
OleMash [197]

Answer:

There isn't a question

Step-by-step explanation:

8 0
2 years ago
Once each day, Erika tracks the depth of the water in her local creek. Her first nine measurements, in inches, are: 16, 15, 13,
solniwko [45]

Answer:

Median = 13

Step-by-step explanation:

We are given the following data:

16, 15, 13, 12, 17, 14, 11, 9, 11

Formula:

Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}

Sorted data: 9, 11, 11, 12, 13, 14, 15, 16, 17

Median =

=\dfrac{9+1}{2}^{th} = 5^{th}\text{ term} = 13

Thus, the median of the given data is 13.

4 0
3 years ago
Is this relationship proportional or non proportional
mamaluj [8]
Non-proportional because all the dots are scattered I believe a proportional chart will have a straight line please correct me if I’m wrong :)
6 0
3 years ago
What is an equation that goes through the point (-7, 10) and is perpendicular to the line -2x-4y=9
algol13

Step-by-step explanation:

m1.m2= -1

(4y = -2x -9)= (y = -1x/2 -9/4)

-1/2.m2= -1

m2 = 2

formula = y - y1 = m2 ( x - x1)

y - 10 = 2 ( x - (-7))

y - 10 = 2x + 14

y = 2x + 24

7 0
3 years ago
The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. The follow
kipiarov [429]

Answer:

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

Step-by-step explanation:

The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. Test if the mean cost has increased.

At the null hypothesis, we test if the mean cost is still the same, that is:

H_0: \mu = 13252

At the alternative hypothesis, we test if the mean cost has increased, that is:

H_1: \mu > 13252

The test statistic is:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

13252 is tested at the null hypothesis:

This means that \mu = 13252

The following year, a random sample of 20 two-year institutions had a mean of $15,560 and a standard deviation of $3500.

This means that n = 20, X = 15560, s = 3500

Value of the test statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{15560 - 13252}{\frac{3500}{\sqrt{20}}}

t = 2.95

P-value of the test and decision:

The p-value of the test is found using a t-score calculator, with a right-tailed test, with 20-1 = 19 degrees of freedom and t = 2.95. Thus, the p-value of the test is 0.0041.

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

7 0
3 years ago
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