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ICE Princess25 [194]
3 years ago
7

Once each day, Erika tracks the depth of the water in her local creek. Her first nine measurements, in inches, are: 16, 15, 13,

12, 17, 14, 11, 9, 11 What is the median of her data?
Mathematics
1 answer:
solniwko [45]3 years ago
4 0

Answer:

Median = 13

Step-by-step explanation:

We are given the following data:

16, 15, 13, 12, 17, 14, 11, 9, 11

Formula:

Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}

Sorted data: 9, 11, 11, 12, 13, 14, 15, 16, 17

Median =

=\dfrac{9+1}{2}^{th} = 5^{th}\text{ term} = 13

Thus, the median of the given data is 13.

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Equivalent decimal are decimal that have the same value. <br><br>True<br>Or<br>False
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True because decimals do have the same number when they are equivalent
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3 years ago
In △ABC, m∠A=39°, a=11, and b=13. Find c to the nearest tenth.
Talja [164]

For this problem, we are going to use the <em>law of sines</em>, which states:

\dfrac{\sin{A}}{a} = \dfrac{\sin{B}}{b} = \dfrac{\sin{C}}{c}


In this case, we have an angle and two sides, and we are trying to look for the third side. First, we have to find the angle which corresponds with the second side, B. Then, we can find the third side. Using the law of sines, we can find:

\dfrac{\sin{39^{\circ}}}{11} = \dfrac{\sin{B}}{13}


We can use this to solve for B:

13 \cdot \dfrac{\sin{39^{\circ}}}{11} = \sin{B}

B = \sin^{-1}{\Big(13 \cdot \dfrac{\sin{39^{\circ}}}{11}\Big)} \approx 48.1


Now, we can find C:

C = 180^{\circ} - 48.1^{\circ} - 39^{\circ} = 92.9^{\circ}


Using this, we can find c:

\dfrac{\sin{39^{\circ}}}{11} = \dfrac{\sin{92.9^{\circ}}}{c}

c = \dfrac{11\sin{92.9^{\circ}}}{\sin{39^{\circ}}} \approx \boxed{17.5}


c is approximately 17.5.

8 0
3 years ago
Which of these statements are true?
Veronika [31]

Answer:

     

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A matatu carries 14 passengers per trip. In
PilotLPTM [1.2K]

Answer:

"23,520"

Step-by-step explanation:

one trip: 14 passengers

one day: 3 trips

passengers: 80

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6 0
3 years ago
It is estimated that 91% of senior citizens suffer from sleep disorders and 9% suffer from anxiety. Moreover, 6% of seniors suff
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The probability of senior citizens suffer from sleep disorders is

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a. The probability that a senior citizen suffers from anxiety, given that he or she has a

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8 0
1 year ago
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