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abruzzese [7]
4 years ago
15

Internet sites often vanish or move so that references to them cannot be followed. In fact, 13 % of Internet sites referenced in

major scientific journals are lost within two years after publication. If a paper contains eight Internet references, what is the probability that all eight are still good two years later? Round your answer to three decimal places. What specific assumption must be made in order to calculate the probability? One does not need to make any assumptions; this is just a straightforward calculation. The paper containing the references must be obtained by random sampling. The occurrence of the site references in the paper are independent events. The occurrence of the site references in the paper are disjoint events, P (all eight are still good) =
Mathematics
1 answer:
Bumek [7]4 years ago
3 0

Answer:

0.328, the occurance of the site references in the paper are independent,

Step-by-step explanation:

Probability that site is lost: p=0.13

Probability that site is good: q= 1-0.13= 0.87

Probability that all eight sites are good= q^8= 0.87^8= 0.328

Paper is not a variable in this question.

all the eight occurances of the site references in the paper must be independent from each other

the probability of occurance of one site is not mutually exclusive from probability of occurance pf another site

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In a certain school there are 180 pupils in the year7,110 pupils study french,88 study German , and 65 indonesian.40 pupils stud
MAXImum [283]

Answer:

(a) All three languages  - 9

(b) Indonesian only  - 10

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(d) At least one language  - 168

(e) Either one or two of the three languages - 159​

Step-by-step explanation:

The question require the knowledge of Set theory and its Formulas.

Total pupils = 180

French (Let F) = 110  

German (Let G) = 88

Indonesian (Let I) =  65

French and German (F intersection G) =  40

German and Indonesian (G intersection I) =  38

French and Indonesian (F intersection I)  = 26

German only  = 19

(a) All three languages

We are given only German speaking people are 19

Only German = n(G) - n( F intersection G) - n(G intersection I) + n(F intersection G intersection I)

 19 = 88 - 40-38 + n(G intersection I) + n(F intersection G intersection I)

n(G intersection I) + n(F intersection G intersection I) = 9

n(G intersection I) + n(F intersection G intersection I) represents the number of pupils speaking who study all the three languages.

(b)Indonesian only

   n( I) - n(G intersection I) + n(F intersection I) + n(G intersection I) + n(F intersection G intersection I)

65 - 38 - 26 + 9 = 10

So 10 pupils speak Indonesian only

(c)none of the languages

It will be equal to Total - pupils speaking any of the three languages

Any of the three languages = (F union G union I)

  = n(F) +n(G) + n(I) -n(F intersection G) - n(G intersection I) -n(F intersection I)

    +  n(F intersection G intersection I)

n(G intersection I)

  = 110 + 88 + 65 -40 -38-26 + 9

  = 263 - 95

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So 168 pupils speak any of the three languages

None speakers = 180 - 168 = 12 pupils

So 12 pupils do not speak any of the three languages.

(d)at least one language

At least one language has the meaning that the person can either speak one two or all three languages, so it will be same as we proceeded above

Any of the three languages = (F union G union I)

  = n(F) +n(G) + n(I) -n(F intersection G) - n(G intersection I) -n(F intersection I)

    +  n(F intersection G intersection I)

n(G intersection I)

  = 110 + 88 + 65 -40 -38-26 + 9

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(e) either one or two of the three languages​

Pupils can speak one or two language but not all the three so will subtract all the three language speaker from the total.

  Total speaker = 168

 All three languages speaker  = 9

 Either one or two of the three languages​ speaker = 168 - 9 = 159

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Answer:

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Maybe from the equation of a line from y=mx+c
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