First subtract 3 from both sides of the equal sign.
9s + 3 = 57
- 3 -3
9s = 54
Then divide both sides by 9.
9s = 54
/9 /9
s = 6
You can check it by plugging it back into the equation.
9s + 3 = 57
9 * 6 + 3= 57
54 + 3 = 37
57 = 57
Yep! It's correct! :)
Hope that helped. Algebra can be tricky sometimes I know but it's really just balancing equations.
This is a combination problem. The approach to this is by using the nCr method, where n is the number of total objects and r is the number of success. For example, if you want to get 3 red out of the total 4, then that would be 4C3. That means,
4C3 = 4!/3!(4 - 3)! = 4 ways
If you want to get 2 green out of the total 6, then that would be 6C2. That means,
6C2 = 6!/2!(6-2)! = 15 ways
Therefore, there are a total of 4+15 = <em>19 ways</em>.
Answer:

Step-by-step explanation:
Given

Quadrant III
Required
Determine 
We have:

We know that:

This gives:


Collect like terms

Take LCM and solve


Take the square roots of both sides

Sin is negative in quadrant III. So:

Calculate 

We have: 
So:


Rationalize


So, we have:



Substitute: 

Take LCM

The rage of the function is x=-6