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In-s [12.5K]
3 years ago
14

est scores for a statistics class had a mean of 79 with a standard deviation of 4.5. Test scores for a calculus class had a mean

of 69 with a standard deviation of 3.7. Suppose a student gets a 84 on the statistics test and a 96 on the calculus test. Calculate the z-score for each test. On which test did the student perform better relative to the other students in each class
Mathematics
1 answer:
Arte-miy333 [17]3 years ago
7 0

Answer:

The z-score for the statistics test grade is of 1.11.

The z-score for the calculus test grade is 7.3.

Due to the higher z-score, the student performed better on the calculus test relative to the other students in each class

Step-by-step explanation:

Z-score:

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

The grade with the higher z-score is better relative to the other students in each class.

Statistics:

Mean of 79 and standard deviation of 4.5, so \mu = 79, \sigma = 4.5

Student got 84, so X = 84

The z-score is:

Z = \frac{X - \mu}{\sigma}

Z = \frac{84 - 79}{4.5}

Z = 1.11

The z-score for the statistics test grade is of 1.11.

Calculus:

Mean of 69, standard deviation of 3.7, so \mu = 69, \sigma = 3.7

Student got 96, so X = 96

The z-score is:

Z = \frac{X - \mu}{\sigma}

Z = \frac{96 - 69}{3.7}

Z = 7.3

The z-score for the calculus test grade is 7.3.

On which test did the student perform better relative to the other students in each class?

Due to the higher z-score, the student performed better on the calculus test relative to the other students in each class

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Answer:

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That equation equals $2,739.58 which you add to the principal.

$2,739.58 + $2,300 = $5039.58

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