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Mandarinka [93]
3 years ago
8

I need to get both into y=mx+b

Mathematics
2 answers:
quester [9]3 years ago
5 0

Isolate the y for both questions. Note that what you do to one side, you do to the other. Do the opposite of PEMDAS.

First question: x - 5y ≥ 3

First, subtract x from both sides

x (-x) - 5y ≥ 3 (-x)

-5y ≥ -x + 3

Divide -5 from both sides. Note that when you divide by a negative number, you flip the equation.

(-5y)/-5 ≥ (-x + 3)/-5

y ≤ (-x + 3)/-5

y ≤ x/5 - 0.6

------------------------------------------------------------------------------------------------

Do the same for the second one. Subtract x from both sides

x + y < 0

x (-x) + y < 0 (-x)

y < - x

~

neonofarm [45]3 years ago
5 0

x-5y≥3

-5y≥3-x

5y≤x-3

y≤(1/5)x-3

The answer to the first equation is y≤(1/5)x-3.

x+y<0

y<-x

The answer to the second equation is y<-x.

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