well, the triangle is an isosceles, so it twin sides, and the twin sides make twin angles, as we see by the tickmarks on A and C, meaning AB = BC.
![\bf x+4=3x-8\implies 4=2x-8\implies 12=2x\implies \cfrac{12}{2}=x\implies 6=x \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ AC\implies x+4\implies 6+4\implies 10](https://tex.z-dn.net/?f=%5Cbf%20x%2B4%3D3x-8%5Cimplies%204%3D2x-8%5Cimplies%2012%3D2x%5Cimplies%20%5Ccfrac%7B12%7D%7B2%7D%3Dx%5Cimplies%206%3Dx%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20AC%5Cimplies%20x%2B4%5Cimplies%206%2B4%5Cimplies%2010)
It is 8.525. what u do is 21÷40 and get .525 and then u add the 8 in the front and get 8.525
The numbers are 15, 17 and 19
3/8=answer
1) 5/8-1/4=
2) <u>(</u><u>5</u><u>•</u><u>4</u><u>)</u><u>-</u><u>(</u><u>1</u><u>•</u><u>8</u><u>)</u><u>=</u>
<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>8•4
3) <u>20-8</u><u> </u>
<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>32 =
4) <u>12</u>
<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>32=
5) <u>12</u><u>/</u><u>4</u>
<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>32/4=
6) <u>3</u>
<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>8 =answer
Answer:
x-73
Step-by-step explanation:
Let x=Jose's height. If it says "less than," then that is subtraction. Since Jose's height is not defined, there is no specific number that can be used to describe "73 less than twice Jose's height," so I use the variable x, and then subtract 73.