Answer: The answer is 50980
Step by Step Explanation:
First, temporarily assume that two letters with I are different, call them i 1 and i 2. Three "a" are also called as a 1, a 2 and a 3, and two h as h 1 and h 2. Then there are 11 * 10 * 9 * 8 * 7 = 55440 possible "words" (one of 11 is the first letter, 10 is the second, and so on). But because equal letters do the same "words," some "words" were counted twice or more. We have to deduct the number of "parasitic" counts although it is fairly small. The words that counted more than once are divided into many disjoint sets: 1) with two I but without repetitions of a and h; 2) with two h but without repetitions of a and I 3) with two a but without repetitions of I and h; 4) with three a but without repetitions of I and h; 5) with two I and two a's; 6) two i's and tree a's; 7) two i's and two h's 8) two h's and two a's; 9) two h's and one tree. The first category includes terms counted twice and its scale is (5 * 4) * (6 * 5 * 4) = 2400 (the first I stays at one of the 5 positions, the second at one of the 4, then 11-2i-1h-2a=6). So we have 2400/2 = 1200 to subtract. Group 2 gives -600 as well, and group 3 also. Group 4 gives * (6 * 5) = 1800 (5 * 4 * 3), and the terms are counted 6 times, -300. Groups 5, 7 , 8: 5 * 4 * 3 * 2 * 6 = 720 and counted four times, therefore -180. Group 6 and 9: 5 * 4 * 3 * 2 * 1 = 120, with 12 counts, -10. Altogether -(1200 * 3 + 300 + 180 * 3 + 10 * 2) = -4460.The answer will be 55440-4460 = 50980.
Answer:
Supplement to ∠ABC: ∠DAB acts as a possible supplement
Step-by-step explanation:
There are two approaches to this problem:
1. We can identify an angle by it's measure such that it adds to 180° when added to the m∠ABC
2. As this shape is a quadrilateral, we can tell that two adjacent angles are supplementary to one another, and thus can be identified as the supplement to ∠ABC
For the simplicity, lets take the second method into consideration. We see that ∠ABC is adjacent to the two angles - ∠BCD, ∠BAD. These angles can be rewritten as such: ∠DCB, ∠DAB. And, as we can see from the options, ∠DAB is one of them that may act as a supplement. Shall we check?
The m∠ABC is 110° (degrees) so that it's claimed supplement, ∠DAB should be 70° as to satisfy the first condition of adding to 180°. And, we can see from the diagram that 40° + 30° = 70° so that both "approaches" are met!
I don't know what you are asking but my best guess is it will be
$4.46 in total
Answer:
100.48 mm
Step-by-step explanation:
Circumference = 2πr
π = 3.14
C = 2(3.14)16mm
C = 6.28(16mm)
C = 100.48mm
Circumference = 100.48
Units: mm
-Chetan K
Answer:
572.1 gm will be left
Step-by-step explanation:
seven days of decay to find how much is still there on the 8th day
1400 ( 1 - .12)^7 =
