The equation has one extraneous solution which is n ≈ 2.38450287.
Given that,
The equation;
We have to find,
How many extraneous solutions does the equation?
According to the question,
An extraneous solution is a solution value of the variable in the equations, that is found by solving the given equation algebraically but it is not a solution of the given equation.
To solve the equation cross multiplication process is applied following all the steps given below.
The roots (zeros) are the x values where the graph intersects the x-axis. To find the roots (zeros), replace y
with 0 and solve for x. The graph of the equation is attached.
n ≈ 2.38450287
Hence, The equation has one extraneous solution which is n ≈ 2.38450287
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brainly.com/question/15070282
Answer:
h<2
Step-by-step explanation:
5×2h+5×8<60
10h+40<60
10h<60-40
<u>1</u><u>0</u><u>h</u><u><</u><u>2</u><u>0</u>
<u>1</u><u>0</u><u>. </u><u> </u><u> </u><u> </u><u>1</u><u>0</u>
h<2
Answer:
Step-by-step explanation:
99
Answer:
u
Step-by-step explanation:
Answer:
D - The elevator traveled upward at a rate of 2(2/5) feet per second.
Step-by-step explanation:
Okay, this is almost like kinematics, which deals with physics.
Here are your given values:
Position 1 = 70ft [down]
Position 2 = 10ft [down]
Change in time (Δt - time - scalar) = 25 seconds
The equation for displacement is d₂-d₁. This would be the change of position of the elevator during the 25 seconds.
So, we can use this equation to figure out the change in position.
Δd = d₂-d₁ = 10ft [down] - 70 ft [down] = 60ft [up]
The equation for velocity is Δd/Δt. This would be the rate of which the elevator travels. Velocity is simply speed but with a direction.
So, we can use this equation to solve.
v = Δd / Δt = 60 feet [up] / 25 seconds = 2.4 ft / second [up].
Now, we need to change 2.4 ft / second [up] into a fraction.
2.4 -> 2 (4/10) -> 2 (2/5)
All I am simply doing is figuring out the distance the elevator traveled and determined the direction of which the elevator traveled. Then, I divided that by the time the elevator traveled to determine its speed and the direction the elevator traveled.
