68-33 blockers ?????????????????????????????????????????!?!!
Answer:
B
Step-by-step explanation:
Data set D does not contain the value 128, which is the median value.
Data set C does not contain the outlier value 91.
Data set A contains value 168, which does not show up on the plot.
The only remaining choice is B.
_____
In order, the data values of set B are ...
... 91, 114, 120, 126, 128, 128 134, 136, 139, 142, 152
The median value of these 11 is the 6th one: 128. The median values of the remaining two sets of 5 are 120 and 139, making these values the quartiles at the ends of the box. The value 91 is more than 1.5 times the IQR (19) below the 1st quartile, so is considered an outlier. (The cutoff is 120-1.5·19=91.5.)
Answer:
x = 30
Step-by-step explanation:
well from the theorem we have
yes i know you could say that the right way is
well if you notice they are the same only that in my way the x is in the numerator which means it will be far easier to know it's value :)
so
![\frac{15}{3}=\frac{x}{6}\\\\5=\frac{x}{6}\\\\6[5]=6[\frac{x}{6}]\\\\30=x](https://tex.z-dn.net/?f=%5Cfrac%7B15%7D%7B3%7D%3D%5Cfrac%7Bx%7D%7B6%7D%5C%5C%5C%5C5%3D%5Cfrac%7Bx%7D%7B6%7D%5C%5C%5C%5C6%5B5%5D%3D6%5B%5Cfrac%7Bx%7D%7B6%7D%5D%5C%5C%5C%5C30%3Dx)
Answer:
tghghgkk
Step-by-step explanation:
