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ycow [4]
3 years ago
9

A principal of $3300 is invested at 8.5% interest, compounded anually. How much will the investment be worth after 11 years? Rou

nd your answer to the nearest dollar. Please help..
Mathematics
1 answer:
yulyashka [42]3 years ago
3 0

Answer:

\boxed{\$8378}

Step-by-step explanation:

The formula for compound interest is:

A = P(1 + r)ⁿ

Data:

    P = 3300

APR = 8.5 %

     t = 11 yr

Calculations:

n = 11 × 12 = 132

r = 0.085/12 = 0.007 083

A = 3300(1 + 0.007 083)¹³²

  = 3300 × 1.007 083¹³²

  = 3300 × 2.5539

  = 8378

\text{The investment will be worth }\boxed{\mathbf{\$8378}}

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Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

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where

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In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

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Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

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substitute in the formula of distance

r=\sqrt{(2-4)^{2}+(-6+3)^{2}}

r=\sqrt{(-2)^{2}+(-3)^{2}}

r=\sqrt{13}\ units

The equation of the circle is equal to

(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}

(x+3)^{2} +(y-4)^{2}=13

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

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(10+3)^{2} +(4-4)^{2}=13

(13)^{2} +(0)^{2}=13

169=13 -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

(x-1)^{2} +(y-3)^{2}=r^{2}

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

r=\sqrt{(6-3)^{2}+(2-1)^{2}}

r=\sqrt{(3)^{2}+(1)^{2}}

r=\sqrt{10}\ units

The equation of the circle is equal to

(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}

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we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

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The point is not on the circle

The statement is false

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